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3 years ago

11

what must happen first before a change of state can occur (change in mass, change in position, change in volume, or change in en

ergy)

1 answer:

SVEN [57.7K]3 years ago

7 0

Answer:

Change in energy.

Explanation:

An energy change is required to shift one state to another or do any of the other listed.

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50.0 mL of an HNO^3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the

NISA [10]

Answer:

0.0738 M

Explanation:

HNO3 +LiOH = LiNO3 + H2O

Number of moles HNO3 = number of moles LiOH

M(HNO3)*V(HNO3) = M(LiOH)*M(LiOH)

M(HNO3)*50.0mL = 0.100M*36.90 mL

M(HNO3) = 0.100*36.90/50.0 M = 0.0738 M

6 0

3 years ago

Que materias o asignaturas disciplinarias consideras que están

zalisa [80]

Las áreas temáticas que pueden estar involucradas en el cuidado del agua son;

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Aprende más: brainly.com/question/10929764

5 0

2 years ago

Need help !!!!! ASAP

gavmur [86]

<h2>Hello!</h2>

The answer is:

The new temperature will be equal to 4 K.

$T_{2}=4K$

<h2>Why?</h2>

We are given the volume, the first temperature and the new volume after the gas is compressed. To calculate the new temperature after the gas was compressed, we need to use Charles's Law.

Charles's Law establishes a relationship between the volume and the temperature at a gas while its pressure is constant.

Now, to calculate the new temperature we need to assume that the pressure is kept constant, otherwise, the problem would not have a solution.

From Charle's Law, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

So, we are given the following information:

$V_{1}=500mL\\T_{1}=20K\\V_{2}=100mL$

Then, isolating the new temperature and substituting the given information, we have:

$\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$

$T_{2}=\frac{T_{1}}{V_{1}}*V_{2} \\$

$T_{2}=\frac{20.00K}{500mL}*100mL\\$

$T_{2}=4K$

Hence, the new temperature will be equal to 4 K.

$T_{2}=4K$

Have a nice day!

7 0

3 years ago

Citric acid has a pH between 1 and 3. It is considered to be a

Tasya [4]

Strong Acid cause it has a very low pH

5 0

3 years ago

Read 2 more answers

How many grams of Al(OH)3 are produced from 3.00 g of AlCl3 with excess of NaOH?

Blizzard [7]

Answer:

1.772 gram is the approximate answer

Explanation:

molecular mass of AlCl3 is 132 g per mole and of Al(OH)3 is 78 g per mole

the reaction is

AlCl3 + 3 NaOH ---> Al(OH)3 + 3 NaCl

from the reaction it is clear that 1 mole AlCl3 makes 1 mole Al(OH)3

implies 132g AlCl3 gives 78g Al(OH)3

Implies 3g AlCl3 gives

3*122/78 = 1.772 grams

3 0

3 years ago