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goblinko [34]
3 years ago
7

Which graph represents the function of f(x) 9x^2 -36 / 3x + 6

Mathematics
1 answer:
Finger [1]3 years ago
7 0

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

f(x)=\frac{9x^{2}-36}{3x+6}

Remember that the denominator cannot be equal to zero

so

The value of x cannot be equal to x=-2

<em>Simplify the numerator</em>

9x^{2}-36=(3x+6)(3x-6) ----> by difference of squares

substitute

f(x)=\frac{(3x+6)(3x-6)}{3x+6}

simplify

f(x)=3x-6

The domain is all real numbers except the value of x=-2

The y-intercept is the point (0,-6) ---> value of y when the value of x is equal to zero)

The x-intercept is the point (2,0) ---> value of x when the value of y is equal to zero)

therefore

The graph in the attached figure

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The sector of a circle with a diameter of 20 inches has a central angle measure of 36°. What is the area of the sector?
Bogdan [553]
We need the radius to find the area of sector.

radius = 20/2 = 10

Area of sector:

πr²(x/360) = x is the central angle in degrees.
π(10)²(36/360)
10π in²

Hope this helps :)
4 0
4 years ago
If s store is selling boxes of pudding at 3 for $0.99,how much would 12 boxes cost
sweet [91]

Answer:

The cost price of 12 boxes of pudding is $3.96

Step-by-step explanation:

Given as :

The quantity of pudding boxes = 3

The cost price for 3 boxes = $0.99

Again ,

The quantity of pudding boxes = 12

Let The cost price for 12 boxes = $x

Now, According to question

<u>Using Unitary method</u>

∵ The cost price of 3 boxes of pudding = $0.99

or,The cost price of 1 boxes of pudding = \dfrac{0.99}{3} = $0.33

∴The cost price of 12 boxes of pudding =$0.33 × 12

I.e x =$3.96

So,The cost price of 12 boxes of pudding = x =$3.96

Hence,The cost price of 12 boxes of pudding is $3.96 Answer

4 0
4 years ago
Which function is graphed? .
lina2011 [118]

Answer:

Need a picture please.

Step-by-step explanation:

6 0
3 years ago
Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that s
RSB [31]
Well, is the function continuous?  yes, is a cubic one, you can graph it if you wish, is continuous all the way, and of course at [ 0, 4] too.

is it differentiable?  you can always look at the graph between 0,4 and is a smooth transition line, thus yes, it is differentiable, but let's check anyway,

\bf \cfrac{dy}{dx}=3x^2-2x-12    its derivative has no asymptotes and therefore no "cusps", so yes, is differentiable all around.

is f(0) = f(4), let's check

f(0) = 0+0+0+3,            f(0) = 3
f(4) = 64 - 16 - 48 + 3,   f(4) = 3

yeap

there must then be a "c" value(s) with a horizontal tangent slope, let's check, is really just the critical points.

\bf \cfrac{dy}{dx}=3x^2-2x-12\implies 0=3x^2-2x-12&#10;\\\\\\&#10;\textit{using the quadratic formula}&#10;\\\\\\&#10;x=\cfrac{-(-2)\pm\sqrt{(-2)^2-4(3)(-12)}}{2(3)}\implies x=\cfrac{2\pm\sqrt{4+144}}{6}&#10;\\\\\\&#10;x=\cfrac{2\pm 2\sqrt{37}}{6}\implies x=\cfrac{2\pm\sqrt{37}}{3}\impliedby \textit{c's}
4 0
3 years ago
4. Amazon executives believe that at least 70% of customers would return a product 2 days after it arrives at their home. A samp
inysia [295]

Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean \mu = p and standard error s = \sqrt{\frac{p(1 - p)}{n}}

In this problem:

  • Sample of 500 customers, hence n = 500.
  • Amazon believes that the proportion is of 70%, hence p = 0.7

The <u>mean and the standard error</u> are given by:

\mu = p = 0.7

s = \sqrt{\frac{p(1 - p)}{n}} = \sqrt{\frac{0.7(0.3)}{500}} = 0.0205

The probability is the <u>p-value of Z when X = 0.68</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.68 - 0.7}{0.0205}

Z = -0.98

Z = -0.98 has a p-value of 0.1635.

0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.

A similar problem is given at brainly.com/question/25735688

7 0
2 years ago
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