Assuming you are solving for x...
Answer:
2000 = 600 + 2/5x ; 3500 ft
How To Solve:
2000 = 600 + 2/5x
Combine multiplied terms into a single fraction
2000 = 600 + 2/5x
2000 = 600 + 2x/5
Subtract 600 from both sides of the equation
2000 = 600 + 2x/5
2000 - 600 = 600 + 2x/5 - 600
Simplify
Subtract the numbers
1400 = 600 + 2x/5 − 600
Subtract the numbers
1400 = 2x/5
Solution
X = 3500
1.)
Between year 0 and year 1, we went from $50 to $55.
$55/$50 = 1.1
The price increased by 10% from year 0 to year 1.
Between year 2 and year 1, we went from $55 to $60.50.
$60.50/$55 = 1.1
The price also increased by 10% from year 1 to year 2. If we investigate this for each year, we will see that the price increases consistently by 10% every year.
The sequence can be written as an = 50·(1.1)ⁿ
2.) To determine the price in year 6, we can use the sequence formula we established already.
a6 = 50·(1.1)⁶ = $88.58
The price of the tickets in year 6 will be $88.58.
Answer:
$960
Step-by-step explanation:
price of one month = total expense/ number of month
= 240/3= $80
therefore persons annual expenses = 80*12= $960