Answer:
The fraction is 1/4
Step-by-step explanation:
we know that
The area of an equilateral triangle, using the law of sines is equal to
where
x is the length side of the triangle
In this problem
Let
b ----> the length side of the regular hexagon
2b ---> the length side of the equilateral triangle
step 1
Find the area of the six triangles
Multiply the area of one triangle by 6
![A=6[x^{2}\frac{\sqrt{3}}{4}]](https://tex.z-dn.net/?f=A%3D6%5Bx%5E%7B2%7D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D)
we have
substitute
step 2
Find the area of the regular hexagon
Remember that, a regular hexagon can be divided into 6 equilateral triangles
so
The area of the regular hexagon is the same that the area of 6 equilateral triangles
we have
substitute
step 3
To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles
Answer:
-3
Step-by-step explanation:
5-2 is three
3 times -2 is -6
-9-(-6) is -3
(2,-3)
When handling problems of this nature make sure you setup the equations.
x = number of times they rent a boat.
Members
Cost = 105 + 9.50x
Non members because members don't have to pay the 105 we leave it out.
Cost = 14.75x
so now to determin when cost would be equal we set the two equations = to each other
105 + 9.50x = 14.75x
now solve for x
105 = 5.25x
20 = x
so they would have to rent 20 times to equal each other.
Answer:
negative because since -90 and -5 are both negative just add and keep it the sign which is -95
hope this helps
have a good day :)
Step-by-step explanation:
Answer:
For the first row, write 5(0)-1 = 0-1. y is equal to -1.
For the second row, write 5(1)-1 = 5-1. y is equal to 4.
For the third row, write 5(2)-1 = 10-1. y is equal to 9.
For the fourth row, w rite 5(3)-1 = 15-1. y is equal to 14.
Step-by-step explanation:
Hope this helps!
