Hi,
Answer: (x+5)^2
<u>My work:</u> For this problem can be easily achieved by factoring your terms. To do this you figure out what can go into 10x and 25 which is 5. From the there you take x^2 and 10x and see what can take out which would be x. Your answer would be (x + 5)^2 or (x +5) (x + 5). This can be done in 2 easy steps!
<u><em>Numerical work:</em></u>
1.x^2 10x +25
Before this step figure out what goes into you equation.
2. (X + 5)^2 or (X+5) (X + 5)
If it is marked down 25% and 25% equals 25/100 then you simply take 39.59 x 25/100
39.59 x 25/100 = 9.90
and then you subtract that from the original price
39.59 - 9.90 = $29.69
after it is marked down, the price is $29.69
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Hi there!
To estimate, we can round:
591.3 is approximately 600
29 is approximately 30
Now, we divide:
600 / 30 = 20
Hope this helps!
Mid point of x:
{2-(-6)} : 2
8 : 2
4
mid point of y:
(5-3) : 2
2 : 2
1
so (4,1)