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3 years ago

Does anyone know -6/7+6/21

1 answer:

4 0

Simple...

you have: $-\frac{6}{7} + \frac{6}{21}$

You must find a common denominator first-->>

$- \frac{6}{7} * \frac{3}{3} = -\frac{18}{21}$

Now...

$- \frac{18}{21} + \frac{6}{21} = -\frac{12}{21}$

$= -\frac{12}{21}$

Simplify it-->> $-\frac{4}{7}$

Thus, your answer.

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make the indicated conversion assume a 360-day year as needed,8months to simplified fraction of a year

balandron [24]

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2 years ago

Choose the equation below that represents the line passing through the point (−2, −3) with a slope of −6.

lubasha [3.4K]

Y = mx + b
slope(m) = -6
(-2,-3)...x = -2 and y = -3
now we sub....we r looking for b, the y int
-3 = -6(-2) + b
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-3-12 = b
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so ur equation is : y = -6x - 15

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2 years ago

Growth or decay: 1/2(10)^x

suter [353]

Answer:

Growth

Step-by-step explanation:

If the base (the number in the parentheses) is less then 1 then it is a decay, and if it's larger than 1 it is a growth.

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2 years ago

In a packet of stickers there are 15 small stars, 7 big stars, 9 small rockets, and 6 big rockets. Kevin is going to choose one

yanalaym [24]

Answer:

31/37

Step-by-step explanation:

There are 15 + 7 + 9 + 6 = 37 total stickers. Of those, 15 + 9 = 24 are small and 15 + 7 = 22 are stars. However, there are 15 small stars so 24 - 15 = 9 of them are only small and 22 - 15 = 7 are only stars. This means that there are 15 + 9 + 7 = 31 stickers that are small or stars, therefore the probability is 31/37.

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2 years ago

Finding Derivatives Implicity In Exercise,Find dy/dx implicity.<br> x2e - x + 2y2 - xy = 0

Klio2033 [76]

Answer:

the question is incomplete, the complete question is

"Finding Derivatives Implicity In Exercise,Find dy/dx implicity . $x^{2}e^{-x}+2y^{2}-xy$ "

Answer : $\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

Step-by-step explanation:

From the expression $x^{2}e^{-x}+2y^{2}-xy$ " y is define as an implicit function of x, hence we differentiate each term of the equation with respect to x.

we arrive at

$\frac{d}{dx}(x^{2}e^{-x )+\frac{d}{dx} (2y^{2})-\frac{d}{dx}xy=0\\$

for the expression $\frac{d}{dx}(x^{2}e^{-x})$ we differentiate using the product rule, also since y^2 is a function of y which itself is a function of x, we have

$(2xe^{-x}-x^{2}e^{-x})+4y\frac{dy}{dx}-x\frac{dy}{dx} -y=0\\\\(2-x)xe^{-x}+(4y-x)\frac{dy}{dx}-y=0 \\$ .

if we make dy/dx subject of formula we arrive at

$(4y-x)\frac{dy}{dx}=y-(2-x)xe^{-x}\\\frac{dy}{dx}=\frac{y-(2-x)xe^{-x}}{(4y-x)}$

5 0

3 years ago