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laila [671]
3 years ago
10

Determine the prime factorization of 88.

Mathematics
2 answers:
madam [21]3 years ago
6 0
The Prime Factors of 88 are:
2 x 2 x 2 x 11

In Exponential Form:
2₃ x 11₁

Prime Factors Tree:
     88               
     /  \               
2         44          
          /  \          
     2         22     
               /  \     
          2         11

Hopefully you understand now! :D

OlgaM077 [116]3 years ago
3 0
None of the answers above are the prime factorization of 88
Each one of them is way too big.

88 can be broken down in 11 x 8
While 11 is prime,  8 is still composite and can be broken down into 2 x 4
The 2 is prime but the 4 is still composite so it can be broken down into 2 x 2, both of which are prime.  So it appears we have (in numerical order smallest to biggest):
2 x 2 x 2 x 11  or    2³  x 11   this is the correct prime factorization of 88.

Check:  2 x 2 x 2 = 8 x 11 = 88

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Answer:

1056

Step-by-step explanation:

Find the area of each square and add them to find the area of the rectangle

The area of a square = side * side

The areas are:

1*1= 1

4*4 = 16

7*7 = 49

8*8 = 64

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10*10 = 100

14*14 = 196

15*15 = 225

18*18 = 324

The sum of the areas =

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2 years ago
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a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

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olga_2 [115]

Answer:

Step-by-step explanation:

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Mrrafil [7]

Answer:

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Step-by-step explanation:

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I need help with these please... anyone?
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