The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
1/2 of the class are 5th and 4th
1/2 of 96= 48
1/4 of 48 =12
Answer:
2(6x-5)
Step-by-step explanation:
Factor 2 out of the expression.
Answer:
x = 
Step-by-step explanation:
Answer: 0.7 is the rate change between the two points
