<h3>
Answer: 3 m/s^2</h3>
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According to Newton's Second Law, we know that
F = m*a
where F is the force applied, m is the mass and 'a' is the acceleration.
We see that this is a direct variation equation for F and a, such that m is the constant of variation. It's similar to how y = kx is also a direct variation equation.
Plug in F = 35 and a = 5 to find m
F = ma
35 = m*5
35/5 = m
7 = m
m = 7
The object has a mass of 7 kg
Our equation F = ma updates to F = 7a
Now plug in the force F = 21 to find 'a'
F = 7a
21 = 7a
21/7 = a
3 = a
a = 3
The acceleration will be 3 m/s^2
Notice how a smaller force applied means that the acceleration has also gone down as well.
3 and 1/3 times 2.5 = 8.3(repeating 3) feet
A)lim(x--->-3) x^2-9/x+3=x-3=-6
k should be -6 in A
B)lim (x---->0) e^x-1/x --HOP-->e^x/1=1
k should be 1 in B
C)lim (x---->1/2) sin(5πx)-1/2x-1 ----hop-->5π*cos(5πx)/2=0
k should be 0 in C
You're first problem is unclear as I am not sure if that t was suppose to be there or not.
but as for the second one (33.7y+8.4-2.04y) we would first have to combine like terms so you'd subtract 2.04y from 33.7y , which would give you ; 33.66y so now your answer would be " 33.66y + 8.4 ",
there's nothing more you can do because they're seperate terms c: .
Your third problem ( 4.2x+8.1x+1.8x-2.1x ) is also combining like terms. Add the first 3 terms and that'll give you 14.1x , now subtract 2.1x and that'll give you "12x" as your final answer ~
For your fourth problem x+2 ( x-y ) , you would have to do something called factoring , basically all you gotta do is distribute term by term. So, x times x would give you x^2 , x times -y would give you -xy , 2 times x is 2x , and 2 times -y is -2y , so that'll look somethng like x^2 - xy + 2x - 2x . Now the 2x's cancel out
and you are left with "x^2 - xy" as your final answer ~
