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notka56 [123]
3 years ago
5

Sorry wrong one!!!!!!!!!!!!!!!!!!!!!!!!!!!!11

Mathematics
2 answers:
murzikaleks [220]3 years ago
6 0

Answer:

heheheeheh

Step-by-step explanation:

kotykmax [81]3 years ago
4 0

Answer: Uhhhhh no question...

Step-by-step explanation:

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The following function represents the production cost f(x), in dollars, for x number of units produced by company 1: f(x) = 0.15
dsp73

Answer: g(x) at (70, 55)

Step-by-step explanation:

The minimum of g(x) is lower than f(x) which is (20, 340) and thats obviously higher than (70, 55) so :)

5 0
3 years ago
Someone please help me with this math question!
stepladder [879]
1.25x + 2.5 \ \textless \  2.75x - 6.5 \\ \\ 2.5 \ \textless \  2.75x - 6.5 - 1.25x \ / \ subtract \ 1.25x \ both \ sides \\ \\ 2.5 \ \textless \  1.5x - 6.5 \ / \ simplify \\ \\ 2.5 + 6.5 \ \textless \  1.5x \ / \ add \ 6.5 \ both \ sides \\ \\ 9 \ \textless \  1.5x \ / \ simplify \\ \\ 6 \ \textless \  x \ / \ divide \ both \ sides \ 1.5 \\ \\ x \ \textgreater \  6 \ / \ change \ sides \\ \\ Answer: x \ \textgreater \  6 (A)
8 0
3 years ago
Read 2 more answers
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
3 years ago
Which of the following rational numbers is equal
mart [117]

where are the numbers am not seeing them

4 0
3 years ago
Which of the following can you determine when you use deduction and start from a given set of rules and conditions?
andrew-mc [135]
Deduction is a term used as inference to a known and validated principle. This is when you analyze points through logic from a given set of rules and conditions. You relate how the situation may conform to the rules. Thus. there is no wrong deduction. If you analyze it to be true, then that must be definitely correct. Therefore, the answer is letter B. What must be true.
5 0
3 years ago
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