Answer:
Parker will have to pay $31 in a month in which he downloaded 50 songs.
Total amount Parker will pay for s songs = 6 + 0.50s
Step-by-step explanation:
Cost per month = $6
Cost of Offline download = $0.50 per song
A. How much total money would
Parker have to pay in a month in which he downloaded 50 songs?
Total amount Parker will pay = $6 + $0.50(50)
= 6 + 25
= $31
Parker will have to pay $31 in a month in which he downloaded 50 songs.
B. How much would
he have to pay if he downloaded s songs?
Total amount Parker will pay for s songs = $6 + $0.50 * s
= $6 + $0.50s
Total amount Parker will pay for s songs = 6 + 0.50s
Answer:
a) y = 9x
b) For every increase of 1 hour the price to rent the lane increases by $9.
c) $27
Step-by-step explanation:
a) Since it costs $18 for 2 hours we can infer that for every 1 hour it costs $9.
So, the equation would look like this:
y = 9x
b) In this context, for every increase of 1 hour the price to rent the lane increases by $9. Like the question gave us, the price for 2 hours cost $18.
c) Plug 3 into the equation:
y = 9(3)
y = 27
Therefore, it costs $27 to rent the lane for 3 hours.
<em>I hope this helps!!</em>
<em>- Kay :)</em>
Answer: Vertex (-2,-15) and therefore the axis of sym will be -2
Step-by-step explanation: Using -b/2a you can deduce that 4x^2 is a, 16x is b and 1 is c. So -b/2a = -16/8 = -2. Then you plug -2 for y and yu should get -15. Then x will be your axis of symetry to x=-2
The first one is 5c√10c/3d^3
The answer is: A, 5c√10c/3d^3
Hope this helps! :)
Answer:

Step-by-step explanation:
Let
, we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:
(1)
(2)
Now we perform the operations: 



(3)
By the quadratic formula, we find the following solutions:
and 
Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

Then, the values of the cosine associated with that angle is:

Now, we have that
, we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used:
(4)
(5)




If we know that
and
, then the value of the function is:

