Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
The graph of the linear equation y = 4x + 3 can be seen at the end of the answer.
<h3>How to find the graph of the given line?</h3>
Here we have the linear equation:
y = 4x + 3.
To graph it, we need to find two points that belong to the line, to do that, we evaluate in two different values of x. I will use x = 0 and x = 2.
When x = 0.
y = 4*0 + 3 = 3
So we have the point (0, 3).
When x = 2:
y = 4*2 + 3 = 8 + 3 = 11
So we have the point (2, 11)
Now we just need to graph these two points and connect them with a line. The graph of the linear equation is the one you can see below.
If you want to learn more about linear equations:
brainly.com/question/1884491
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Omg don’t catfish it’s so damaging to your own self confidence!
Answer: The answer is 144 I believe
Answer:
Interest: £23.4
Amount: £101.4
Step-by-step explanation:
6 × 5/100 × 78 = 23.4
Balance: 78 + 23.4 = 101.4
