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3 years ago

What is 1.8 x 2.4 Find the missing partial products PLEASE HELP!!

Mathematics

1 answer:

horrorfan [7]3 years ago

7 0

Answer: 4.32

Step-by-step explanation: 1.8 x 2.4 is 4.32!

0.8 x 2 = 1.6

0.4 x 0.8 = 0.32

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I have a math problem. I don't know were to start here's my problem. You have 3 cards in front of you, on one side there's a let

Ksenya-84 [330]

The answer will be 21

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4 years ago

You are a meteorologist that places temperature sensors all of the world, and you set them up so that they automatically e-mail

solniwko [45]

Answer:

If the first e-mail you got from sensor S indicates a daily high over 80 degrees, the probability that the sensor is placed in Maine = 0.01156

Step-by-step explanation:

Let the probability of placing the sensor S at Maines be P(M) = 0.05

Probabilty of placing the sensor S in the Sahara desert = P(S) = 1 - P(M) = 1 - 0.05 = 0.95 (this is because the meteorologist is confident that the sensor is at either of the two places.

Let the probability of a high temperature of 80 degrees or more = P(T)

Probability of the sensor picking up temperature of 80 degrees or more given that it is in Maine = P(T|M) = 20% = 0.20

Probability of the sensor picking up temperature of 80 degrees or more given that it is in the Sahara desert = P(T|S) = 90% = 0.90

From the definition of rhe conditional probability

P(A|B) = P(A n B) ÷ P(B)

P(A n B) = P(A|B) × P(B)

If the first e-mail you got from sensor S indicates a daily high over 80 degrees, what is the probability that the sensor is placed in Maine?

The required probability = P(M|T)

P(M|T) = P(M n T) ÷ P(T)

P(T) = P(M n T) + P(S n T)

P(M n T) = P(T|M) × P(M) = 0.20 × 0.05 = 0.010

P(S n T) = P(T|S) × P(S) = 0.90 × 0.95 = 0.855

P(T) = 0 010 + 0.855 = 0.865

P(M|T) = P(M n T) ÷ P(T)

P(M|T) = (0.010/0.865) = 0.01156

Hope this Helps!!!

7 0

3 years ago

In a class of 28 students, 11 have a brother and 9 have a sister. There are 2 students

Westkost [7]

Answer:

$\displaystyle P(A\mid B)=\frac{2}{11}$

Step-by-step explanation:

<u>Conditional Probability</u>

Is a measure of the probability of the occurrence of an event, given that another event has already occurred. If event B has occurred, then the probability that event A occurs is given by:

$P(A\mid B)={\frac {P(A\cap B)}{P(B)}}$

Where $P(A\cap B)$ is the probability that both events occur and P(B) is the probability that B occurs.

Let's define events A and B for the question. There are 11 students that have a brother and 9 that have a sister. Two of those students have a brother and a sister.

We are given the fact that the selected student has a brother: this is the event that has already occurred, thus:

B = A student has a brother

A = A student has a sister

The probability that a student has a brother is:

$\displaystyle P(B)=\frac{11}{28}$