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Nadya [2.5K]
3 years ago
10

What is 1.8 x 2.4 Find the missing partial products PLEASE HELP!!

Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

Answer: 4.32

Step-by-step explanation: 1.8 x 2.4 is 4.32!

0.8 x 2 = 1.6

0.4 x 0.8 = 0.32

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Find the value of y in the diagram below
elena55 [62]

we \: can \: tell \: that \\ 1. \:  \: 13x - 26 = 7x + 16 \\ 2. \:  \: 7 x + 16  + 9y + 7  = 180\\ from \: 1. \\ 6x = 42 \: so \: x = 7 \\ from \: 2. \\ y = 12
3 0
3 years ago
Read 2 more answers
A man travels 20 km by car from Town P to Town Q at an average speed of x km/h. He finds that the time of the journey would be s
yuradex [85]

Answer:

x = 20.

Step-by-step explanation:

First, you should remember the relation:

Distance = Speed*Time.

First, we know that a man travels a distance of 20km at a speed of x km/h, in a time T.

We can write this as:

20km = (x km/h)*T

We know that the time is shortened by 12 minutes if the speed is increased by 5km/h

Rewriting these 12 minutes in hours (remember that 60min = 1 hour)

12 min = (12/60) hours = 0.2 hours

Then from this, he can travel the same distance of 20km in a time T minus 0.2 hours if the speed is increased by 5 km/h

We can write this as:

20km = (x + 5 km/h)*(T - 0.2 h)

Then we have a system of two equations, and we want to find the value of x:

20km = (x km/h)*T

20km = (x + 5 km/h)*(T - 0.2 h)

First, we should isolate the variable T in one of the equations, if we isolate it in the first one, we will get:

20km/(x km/h) = T

Replacing that in the other equation we get:

20km = (x + 5 km/h)*(T - 0.2 h)

20km = (x + 5 km/h)*( 20km/(x km/h) - 0.2 h)

Now we can solve this for x.

Removing the units (that we know that are correct) so the math is easier to read, we get:

20 = (x + 5)*(20/x - 0.2)

We only want to solve this for x.

20 = x*20/x - x*0.2 + 5*20/x - 5*0.2

20 = 20 - 0.2*x + 100/x - 1

subtracting 20 in both sides we get:

20 - 20 = 20 - 0.2*x + 100/x - 1 - 20

0 = -0.2*x + 100/x - 1

If we multiply both sides by x we get:

0 = -0.2*x^2 + 100 - x

-0.2*x^2 - x + 100 = 0

This is just a quadratic equation, we can solve it using the Bhaskara's equation, the solutions are:

x = \frac{-(-1) \pm \sqrt{(-1)^2 - 4*(-0.2)*100} }{2*-0.2}  = \frac{1 \pm 9 }{-0.4}

Then the two solutions are:

x = (1 + 9)/-0.4 = -25

x = (1 - 9)/-0.4 = 20

As x is used to represent a speed, the negative solution does not make sense, so we should use the positive one.

x = 20

then the average speed initially is 20 km/h

3 0
2 years ago
(fractions) 8/9 + 3/18
SVEN [57.7K]

Answer:

13/18

Step-by-step explanation:

s t u p i d

5 0
3 years ago
100 points! Please help asap! Look at the picture attached. My teacher said that both 1 and 2 are neither can someone explain wh
Neko [114]

Answer:

Your teacher is right, there is not enough info

Step-by-step explanation:

<h3>Question 1</h3>

We can see that RS is divided by half

The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS

So P is not on the perpendicular bisector of RS

<h3>Question 2</h3>

We can see that PD⊥DE and PF⊥FE

There is no indication that PD = PF or ∠DEP ≅ FEP

So PE is not the angle bisector of ∠DEF

6 0
3 years ago
Drag each number to the correct location on the equations. Each number can be used more than once, but not all numbers will be u
7nadin3 [17]

The system of equations to find the cost of one adult ticket, a, and the cost of one child ticket, c are Roy's; 6a+2c=66 Elisa's 5a+4c=62.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let's consider adults tickets be a and child tickets be c

so

Roy's purchase

6a+2c=66------1

Elisa's purchase

5a+4c=62-------2

Hence,  the system of equations

6a+2c=66------1

5a+4c=62-------2

solving simultaneously

6a+2c=66

5a+4c=62

Also,

 12a+4c=132

-5a+4c=62

  7a=70

a=$10

put  a=70 in 1

6(10)+2c=66

60+2c=66

2c=66-60

2c=6

c=$3

Learn more about equations here;

brainly.com/question/10413253

#SPJ1

4 0
1 year ago
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