Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
Answer:
I graphed this...
Step-by-step explanation:
It is not linear because it is not a strait line and it doesnt go through the middle!
Hope this helps! :)
Answer:
w= 1 and w= -5/9
Step-by-step explanation:
Because you have an absolute value that means that there are 2 possibilities
either (3x +4) is positive or negative. Will work each case and that will give us the answers.
If (3x+4) is positive we have the equation
3w+ 4 = 6w +1 , subtract 3w from both sides
4 = 6w-3w+1, subtract 1 from both sides
4-1 = 6w-3w, combine like terms
3 = 3w , divide both sides by 3
1 = w
If (3x+4) is negative we have the equation
-(3w+ 4) = 6w +1 , distribute the negative sign in parentheses
-3w -4 = 6w +1, add 3w and subtract 1 from both sides of the equation
-4 -1 = 6w +3w, combine like terms
-5 = 9w , divide both sides by 9
(-5/9) = w
Y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16
