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Margarita [4]
3 years ago
7

Solve6x+5y=3 2x-3y=-13​

Mathematics
2 answers:
babymother [125]3 years ago
6 0

Answer:

(x,y)=(-2,3)

Step-by-step explanation:

6x+5y=3

x=-(13/2)+(3/2)y

6(- 13/2+3/2y) +5y=3

y=3

x=13/2+3/2x3

x=2

Diano4ka-milaya [45]3 years ago
6 0

Step-by-step explanation:

let 6x+5y=3 be equation 1

and 2x-3y=-13 be equation 2

Multiply equation 2 by 3

(2x-3y)*3=(-13)*3

6x-9y=-39

Now Solving eq 1 and 2 simultaneously

6x+5y=3

6x-9y=-39

- + =+

_________

0+14y=42

y=42/14

y=3

Put y=3 in eq 1 to find x

6x+5y=3

6x+5(3)=3

6x+15=3

6x=3-15

6x=-12

x=-12/6

x=-2

Therefore y=3

x=-2

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Dmitriy789 [7]

Answer:

\huge{ \boxed{ \bold{ \sf{y =  - 2x + 6}}}}

☥ \tt{Question} :

  • Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).

☥ \tt{Step  -  \: by \:  -  \: step \: explanation}

☪ \underline{ \underline{ \text{Given : }}}

  • Slope ( m ) = -2
  • Given point = ( - 1 , 8 )

☪ \underline {\underline{ \text{To \: find}}} :

  • Equation of a line in slope - intercept form ( i.e y = mx + c )

Let the point ( -1 , 8 ) be ( x₁ , y₁ )

☪ \underline{ \underline{ \text{Solution}}} :

\underline{ \sf{y - y1 = m(x - x1)}}

plug the known values :

↦ \text{y - 8 =  - 2 \{ x - ( - 1) \} }

↦ \text{y - 8 =  - 2(x + 1)}

Distribute -2 through the parentheses :

↦ \text{y - 8 =  - 2x - 2}

Transpose 8 to right hand side and change it's sign

↦ \text{y =  - 2x - 2 + 8}

↦ \boxed{ \text{y =  - 2x + 6}}

And we're done !

Hope I helped!

♡ Have a wonderful day / night ツ

~TheAnimeGirl ♪

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4 0
2 years ago
Read 2 more answers
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

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6 0
1 year ago
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Bezzdna [24]

Answer: 32 and 42

Step-by-step explanation:

5j +12

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6 0
2 years ago
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viva [34]
The original price was 725.
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So, if the original price was x, 464=0.64x
Solve this by dividing both sides by 0,64:
725=x
So, the original price was 725.
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3 years ago
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Answer:

468

Step-by-step explanation:

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2 years ago
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