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Korolek [52]
3 years ago
10

Which of the following if the value of x?

Mathematics
2 answers:
Yuri [45]3 years ago
6 0

Answer:

i dont know what the options are but i think it's X=14

Step-by-step explanation:

Hope this helps

krek1111 [17]3 years ago
3 0

Answer:

i think it will be 14

Step-by-step explanation:

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The sum of 42 and x is equal to 97.45. What's the equation for the sentence?!! Help!
gogolik [260]

Answer:

X = 97.45 - 42

Step-by-step explanation:

If 42 + X = 97.45, X needs to be 97.45 - 42

you can do the same thing with smaller numbers, for example:

5 + X = 7

7 - 5= 2 and you can check for sure that this is the answer by adding them together 5 + 2= 7 so it's definitely the right answer

so for this question, 97.45- 42 = 55.45 so that's X

you can check that by 55.45 + 42 and if the answer is 97.45 that's the right answer!

I hope that makes sense

8 0
3 years ago
Please help!<br> Subtract h + 3 ​​from​ 6h + 1.
cricket20 [7]
6h+1-h+3
=5h+4
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4 0
3 years ago
Evaluate<br> 3.r” + 2y when r<br> 3 and y<br> 3
aleksandr82 [10.1K]

Answer:

first 2x3= 6

3.3 + 6 = 9,3

answer should be 9,3

3 0
3 years ago
How do I fine the sun and difference of number 16?
Julli [10]
Difference=subtract sum=add. just answering so you don't waste points :-)
6 0
4 years ago
A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco
IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}

The probability of rolling a number greater than 3 is:

\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}

Events A and B are independent, then the probability of one happening after the other is:

\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}

8 0
1 year ago
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