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1.)Which of the following is an appropriate action if you are caught outside in a thunderstorm?

arsen [322]

Answer:

1) Squat down low and cover your head. (if no shelters are present)

2) 1 gallon per person per day

8 0

3 years ago

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A 275-mL flask contains pure helium at a pressure of 752 torr. A second flask with a volume of 475 mL contains pure argon at a p

hichkok12 [17]

Answer:

Partial pressure He = 276 torr

Partial pressure Ar = 457 torr

Total pressure = 733 torr

Explanation:

Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.

Once the two flasks are connected and the stopock opened, the total volume is:

275 + 475 = 750 mL

Now we use Boyle's law twice, to calculate the new pressure of each gas:

He ⇒ 752 torr * 275 mL = P₂He * 750 mL

P₂He = 276 torr

Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL

P₂Ar = 457 torr

Finally we calculate the total pressure, adding the partial pressures:

Total pressure = P₂He + P₂Ar = 733 torr

4 0

3 years ago

16. Why do the atoms of H, O, N, F, CI, I, and Br have tendencies to bond with themselves?

Natasha2012 [34]

Because they are elements

6 0

3 years ago

If a chemical appears on the periodic table, it is a(n), ____________

Andre45 [30]

0 plus 5 negative and accumulated

7 0

3 years ago

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K

Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

$\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S$

Thus, by combining them, we obtain:

$-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}$

Which is related to the general line equation:

$y=mx+b$

Whereas:

$y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}$

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0

3 years ago