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belka [17]
3 years ago
8

By what factor must the absolute temperature of a gas be increased to increase the rms speed of its molecules by a factor of 3?

Chemistry
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

The temperature of the molecule will be increased by a factor of 9

Explanation:

The relationship between the temperature and the rms speed of a gas is given by

Vrms=√(3RT/MM)

Where R = Universal gas constant

T = Absolute temperature of the gas in kelvin

MM = Molar mass of the gas

Since from the question, only the rms speed and the temperature are said to change, the term 3R/MM can be represented by a constant k. The relationship then becomes Vrms=√kT  

At the intitial speed, temperature = T1

Vrms=√(kT1 )     (1)

When the speed is increased by a factor of 3, the relationship becomes

(3V)rms=√(kT2 )     (2)

Dividing equation (2) by equation (1)

(3V)rms/Vrms =√(kT2 )/√(kT1 )

3=√(T2/T1 )

T2/T1 =9

The temperature of the molecule will be increased by a factor of 9

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4 0
1 year ago
A particular laser consumes 130.0 Watts of electrical power and produces a stream of 2.67×1019 1017 nm photons per second.
solniwko [45]

The missing question is:

<em>What is the percent efficiency of the laser in converting electrical power to light?</em>

The percent efficiency of the laser that consumes 130.0 Watt of electrical power and produces a stream of 2.67 × 10¹⁹ 1017 nm photons per second, is 1.34%.

A particular laser consumes 130.0 Watt (P) of electrical power. The energy input (Ei) in 1 second (t) is:

Ei = P \times t = 130.0 J/s \times 1 s = 130.0 J

The laser produced photons with a wavelength (λ) of 1017 nm. We can calculate the energy (E) of each photon using the Planck-Einstein's relation.

E = \frac{h \times c }{\lambda }

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E = \frac{h \times c }{\lambda } = \frac{6.63 \times 10^{-34}J.s  \times 3.00 \times 10^{8} m/s }{1017 \times 10^{-9} m }= 6.52 \times 10^{-20} J

The energy of 1 photon is 6.52 × 10⁻²⁰ J. The energy of 2.67 × 10¹⁹ photons (Energy output = Eo) is:

\frac{6.52 \times 10^{-20} J}{photon} \times 2.67 \times 10^{19} photon = 1.74 J

The percent efficiency of the laser is the ratio of the energy output to the energy input, times 100.

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You can learn more about lasers here: brainly.com/question/4869798

8 0
2 years ago
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kenny6666 [7]
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3 years ago
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3 years ago
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OLga [1]

Answer:

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Explanation:

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