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belka [17]
3 years ago
8

By what factor must the absolute temperature of a gas be increased to increase the rms speed of its molecules by a factor of 3?

Chemistry
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

The temperature of the molecule will be increased by a factor of 9

Explanation:

The relationship between the temperature and the rms speed of a gas is given by

Vrms=√(3RT/MM)

Where R = Universal gas constant

T = Absolute temperature of the gas in kelvin

MM = Molar mass of the gas

Since from the question, only the rms speed and the temperature are said to change, the term 3R/MM can be represented by a constant k. The relationship then becomes Vrms=√kT  

At the intitial speed, temperature = T1

Vrms=√(kT1 )     (1)

When the speed is increased by a factor of 3, the relationship becomes

(3V)rms=√(kT2 )     (2)

Dividing equation (2) by equation (1)

(3V)rms/Vrms =√(kT2 )/√(kT1 )

3=√(T2/T1 )

T2/T1 =9

The temperature of the molecule will be increased by a factor of 9

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Explanation:

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How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207:
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<u>Analysing the Question:</u>

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

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If you had 240 L container at 479 k and 300 kpa, what would the volume be if you changed the conditions to STP
nydimaria [60]

Answer:

The answer to your question is V2 = 434.7 l

Explanation:

Data

Volume 1 = V1 = 240 l                             Volume 2 = ?

Temperature 1 = T1 = 479°K                   Temperature 2 = T2 = 293°K

Pressure 1 = P1 = 300 KPa                      Pressure 2 = P2 = 101.325 Kpa

Process

1.- Use the combined gas law to solve this problem

                P1V1/T1 = P2V2/t2

-Solve for V2

               V2 = P1V1T2 / T1P2

2.- Substitution

                V2 = (300)(240)(293) / (479)(101.325)

3.- Simplification

                V2 = 21096000 / 48534.675

4.- Result

                V2 = 434.7 l

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3 years ago
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