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4 years ago

By what factor must the absolute temperature of a gas be increased to increase the rms speed of its molecules by a factor of 3?

Chemistry

1 answer:

attashe74 [19]4 years ago

6 0

Answer:

The temperature of the molecule will be increased by a factor of 9

Explanation:

The relationship between the temperature and the rms speed of a gas is given by

Vrms=√(3RT/MM)

Where R = Universal gas constant

T = Absolute temperature of the gas in kelvin

MM = Molar mass of the gas

Since from the question, only the rms speed and the temperature are said to change, the term 3R/MM can be represented by a constant k. The relationship then becomes Vrms=√kT

At the intitial speed, temperature = T1

Vrms=√(kT1 ) (1)

When the speed is increased by a factor of 3, the relationship becomes

(3V)rms=√(kT2 ) (2)

Dividing equation (2) by equation (1)

(3V)rms/Vrms =√(kT2 )/√(kT1 )

3=√(T2/T1 )

T2/T1 =9

The temperature of the molecule will be increased by a factor of 9

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Answer:

R = 0.064 dm³ atm K⁻¹ mol⁻¹

Explanation:

Answer:

Explanation:

Data Given:

volume of gas V = 8.8 dm³

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Pressure P = 259,392.00 Pa

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101,325 Pascals = 1 atm

So,

259,392.00 Pa = 2 atm

Then Pressure (P) = 2 atm

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change the temperature from °C to K

As to convert °C to K the below formula used

0°C + 273.15 = 273.15K

So, for 2 °C

2°C + 273.15 = 275.15 K

So,

Temperature T = 275.15 K

ideal gas constant = ?

formula used for Ideal gases

PV = nRT

as we have to find R of the gas:

we will rearrange the ideal gas equation as below:

R = PV / nT ........................................... (1)

Put value in equation (1)

R = 2atm x 8.8 dm³ / 1 mole x 275.15 K

R = 17.6 atm. dm³ / 275.15 mol. K

R = 0.064 dm³ atm K⁻¹ mol⁻¹

So the value of R is 0.064 dm³ atm K⁻¹ mol⁻¹

and the unit of R (ideal gas constant) is dm³ atm K⁻¹ mol⁻¹

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3 years ago

Why is thre no gas bubble whene there is citric acid?answer all the questions in detail.

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Answer:

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3 years ago

In a hospital laboratory, a 10.0 mL sample of gastric juice (predominantly HCl), obtained several hours after a meal, was titrat

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To calculate the molarity of acid, we use the equation given by neutralization reaction:

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where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=10.0mL\\n_2=1\\M_2=0.1M\\V_2=7.2mL$

Putting values in above equation, we get:

$1\times M_1\times 10.0=1\times 0.1\times 7.2\\\\M_1=0.072M$

To calculate pH of gastric juice:

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3 years ago

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