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Lena [83]
3 years ago
14

What is the y-intercept of y = 2/3x + 2? (There is no picture shown)

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
6 0

Answer:

2 is the y-intercept.  This is a y=mx+b. This is a linear equation so your m is your slope. The b is the y-intercept. The b is 2 making 2 your y-intercept.

It is 0,2.

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Question 9 of 25
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Answer:

One approach to this problem is to obtain the graph for the given equation.

We need to find every intersection those functions have with the axis 'x' and 'y'

starting with g(x)

g(x=0)=0-3, first point (0,-3) it iis the crossing point with 'x' axis

g(x)=0=x-3, second point (3,0) it iis the crossing point with 'y' axis

Lets do the same for f(x)

g(x=0)=0, this leads to the first point (0,0) it iis the crossing point with 'x' axis and also, with the 'y' axis

We dont need to find any other, since always y=x

By plotting we have the attached picture

Now you can see that g(x) differs from its parent function in that is shifted 3 units to the right, and also 3 units down.

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Pleaseee helpppp!!!!!!!!!!!!!!!!
SVETLANKA909090 [29]
The line g(x) has slope ...
  (change in y)/(change in x) = (-18 -(-20))/(1 - 0) = 2
so can be written in slope-intercept form as
  g(x) = 2x -20

The x-intercept of this line is at x=10.
  0 = 2x -20 . . . . the x-intercept is where g(x) = 0
  20 = 2x
  10 = x

The circle also intersects the x-axis at x=10, so that will be one point that is shared by the circle and g(x). A graph shows there is also another point of intersection, (6, -8).

Yes, the linear function g(x) will intersect the circle at 2 points with positive x-coordinates.

5 0
3 years ago
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