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2 years ago

Please help! Simplify the rational expression. State any restrictions on the variable.

Mathematics

1 answer:

alukav5142 [94]2 years ago

6 0

Step-by-step explanation:

t^2-4xt-12/t-8

= -(t^2-4-6)/4

= -t^2+4+6/4

= -t^2+6

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Which of the following is another way to show the ratio 13 to 27?

Alisiya [41]

Another ratio of 13:27 is to write it as a fraction. This is to mean;
$\frac{13}{27}$

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3 years ago

Solve the equation m²+4m=-2

UNO [17]

Step 1: Subtract -2 from both sides.
m2+4m−(−2)=−2−(−2)
m2+4m+2=0
Step 2: Use quadratic formula with a=1, b=4, c=2.
m=−b±√b2−4ac2a
m=−(4)±√(4)2−4(1)(2)2(1)
m=−4±√82
m=−2+√2 or m=−2−√2

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3 years ago

Read 2 more answers

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Answer:

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Step-by-step explanation:

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2 years ago

What is the value of sin 2900 + cos 2900 ?

Rzqust [24]

Answer:

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Step-by-step explanation:

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2 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

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3 years ago