Answer:
Vf = 23 m/s
Explanation:
First we need to find the distance covered by the motorcycle 2 when it passes motorcycle 1. Using the uniform speed equation for motorcycle 1:
s₁ = v₁t₁
where,
s₁ = distance covered by motorcycle 1 = ?
v₁ = speed of motorcycle 1 = 6.5 m/s
t₁ = time = 10 s
Therefore,
s₁ = (6.5 m/s)(10 s)
s₁ = 65 m
Now, for the distance covered by motorcycle 2 at the meeting point. Since, the motorcycle started 50 m ahead of motorcycle 2. Therefore,
s₂ = s₁ + 50 m
s₂ = 65 m + 50 m
s₂ = 115 m
Now, using second equation of motion for motorcycle 2:
s₂ = Vi t + (1/2)at²
where,
Vi = initial velocity of motorcycle 2 = 0 m/s
Therefore,
115 m = (0 m/s)(10 s) + (1/2)(a)(10 s)²
a = 230 m/100 s²
a = 2.3 m/s²
Now, using 1st equation of motion:
Vf = Vi + at
Vf = 0 m/s + (2.3 m/s²)(10 s)
Vf = 23 m/s
Answer: 1.6m/s
Explanation:
M1 = 13500kg
U1 = 4.5m/s
M2 = 25000kg
U2 = 0m/s (since the body is at rest)
V = ? (Common velocity or velocity after impact)
M1U1 + M2U2 = (M1 + M2)V
But U2 = 0
M1U1 = (M1 + M2)V
13500 * 4.5 = (13500 + 25000)v
60750 = 38500v
V = 60750 / 38500 = 1.5779 = 1.6m/s
Acceleration = (change in speed) / (time for the change)
Change in speed = (ending speed) - (starting speed)
= (7.0 m/s) - (0.8 m/s) = 6.2 m/s
Time for the change = 15 seconds
Acceleration = (6.2 m/s) / (15 sec)
= (6.2/15) m/s²
= 0.413 m/s²
Answer:
Radiology plays a huge role in disease management by giving physicians more options, tools, and techniques for detection and treatment. Diagnostic imaging allows for detailed information about structural or disease-related changes. With the ability to diagnose during the early stages, patients may be saved.
Explanation:
A. Equal and opposite
For every action, there is an equal and opposite reaction
