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astraxan [27]
4 years ago
8

Spinning satellites are particularly stable. suppose that the astronauts launching a particular satellite decide to increase its

angular velocity by a factor of 5. how will that change affect the satellite's angular momentum?
Physics
1 answer:
Crank4 years ago
3 0
Supposing velocity is speed and direction, and momentum is mass*velocity, if the velocity increases by a factor of 5, then so should the momentum regardless of the whole space thing.
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What kind of rock/mineral is wall board made out of?
Aleks04 [339]
Calcium sulfate hope this helps


7 0
4 years ago
Read 2 more answers
A 2.5 x 10^3 kilogram truck with rubber tires moves
ArbitrLikvidat [17]

Answer:

The question implies that force of friction is 2.1E4 N

F = M v^2 / R       frictional force needed to supply this centripetal force

2.1E4 = M v^2 / R

v^2 = R * 2.1E4 / M

v^2 = 120 * 2.1E4 / 2.5E3 = 1200 * 2.1 / 2.5 = 1008 m^2/s^2

v = 31.7 m/s    max speed of truck     (about 70 MPH)

3 0
3 years ago
A 2.9 gram bullet is shot into a tree stump. It enters at a velocity of 304 m/sec and comes to rest after having penetrated the
Helga [31]
First convert grams to kilograms (so that the answer will be N) 1000g=1kg so 2.9g=.0029kg.

To solve for force we use the equation F=ma, so we need to find acceleration (a) .Next use the equation a=Δv/Δt. Δt is given as being .00043 seconds. Δv is the difference in velocities - final minus initial (this is important to discern the direction of the force vector); 0-304=-304. Now plugin and solve for a. The result is -706976.7442 m/s², or -710000 m/s² if you are using significant figures. 

Now use the values for mass and acceleration to solve for force. F=ma=-2050.232558N or F=- 2100N (if you are using significant figures).
7 0
4 years ago
A football is kicked from a tee at 12 m/s at 72° above the horizontal. What is the maximum height of the football
ale4655 [162]
The maximum height is reached when the vertical component of the velocity is zero.

vertical direction:
acceleration: a = -g = -9.81m/s²
velocity: v = -g*t + v₀
position: y = -0.5*g*t² + v₀*t + y₀

For v= 0:
0 = -g*t + v₀ => t = v₀/g 
Insert into position equation gives:
y(max) = (-0.5*v₀²/g) + (v₀²/g) + y₀ = (0.5*v₀²/g) + y₀

6 0
4 years ago
Acceleration is calculated by taking the change in velocity and dividing by the time. What is the
netineya [11]

Answer:

m/s/s

Explanation:

Acceleration is change in velocity over time.

a = Δv / t

a = [m/s] / [s]

a = [m/s/s]

4 0
3 years ago
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