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Arte-miy333 [17]
2 years ago
6

How does proximity to oceans affect Temperatures and rainfall amounts?

Physics
1 answer:
vampirchik [111]2 years ago
4 0

Answer:

Because they absorb and emit heat more steadily than land, oceans help moderate temperatures in coastal areas, making winters warmer and summers cooler. Winds that blow in from across the oceans bring more rainfall and higher humidity.

Explanation:

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Find the energy released when there is a decrease of 0.3kg of material in a nuclear reaction
MrRissso [65]

Answer:

E = 2.7 x 10¹⁶ J

Explanation:

The release of energy associated with the mass can be calculated by Einstein's mass-energy relation, as follows:

E = mc^2

where,

E = Energy Released = ?

m = mass of material reduced = 0.3 kg

c = speed of light = 3 x 10⁸ m/s

Therefore,

E = (0.3\ kg)(3\ x\ 10^8\ m/s)^2

<u>E = 2.7 x 10¹⁶ J</u>

4 0
2 years ago
Why is Tycho Brahe often called “the greatest naked-eye astronomer” of all time?
riadik2000 [5.3K]

Answer:Explained Below

Explanation:

Tycho Brahe saw a super nova which inspired him to study astronomy.His observations are 5 times more accurate than other astronomers of his time   and thus he was given a private island to study about astronomy  .He made most accurate naked eye measurements ever.

So he can be said to be the "greatest naked eye astronomer of all time"

6 0
3 years ago
In 1965, a group of students wore black arm bands to school in protest of American policies in Vietnam. Administrators banned th
Ede4ka [16]

Answer:

protected under students first amendment rights

Explanation:

did the studyisland :)

4 0
3 years ago
A roadrunner is running along a straight desert road at a constant velocity of 25 m/s. If a certain coyote wants to capture the
andreyandreev [35.5K]

Answer:

t = 1.42 s and d = 35.5 m

Explanation:

Given that,

Velocity of a roadrunner is 25 m/s

A certain coyote wants to capture the roadrunner using a net dropped from an overpass that is 10 m high.

We need to find the time before the roadrunner is under the overpass and  how far away from the overpass is the roadrunner when the coyote drops the net.

d=ut+\dfrac{1}{2}at^2\\\\\text{Here, u = 0 and a = g}\\\\d=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2d}{g}} \\\\t=\sqrt{\dfrac{2\times 10}{9.8}} \\\\t=1.42\ s

Let d is the distance traveled. So,

d = vt

d = 25 m/s × 1.42 s

d = 35.5 m

5 0
3 years ago
An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3
ryzh [129]

Speed of the car given initially

v = 18 m/s

deceleration of the car after applying brakes will be

a = 3.35 m/s^2

Reaction time of the driver = 0.200 s

Now when he see the red light distance covered by the till he start pressing the brakes

d_1 = v* t

d_1 = 18* 0.200 = 3.6 m

Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

v_f^2 - v_i^2 = 2 a s

here

vi = 18 m/s

vf = 0

a = - 3.35

so now we will have

0^2 - 18^2 = 2*(-3.35)(s)

s = 48.35 m

So total distance after which car will stop is

d = d_1 + d_2

d = 48.35 + 3.6 = 51.95 m

So car will not stop before the intersection as it is at distance 20 m

3 0
3 years ago
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