Answer:
Sound vibrations travel in a wave pattern, and we call these vibrations sound waves. Sound waves move by vibrating objects and these objects vibrate other surrounding objects, carrying the sound along. ... Sound can move through the air, water, or solids, as long as there are particles to bounce off of.
Explanation:
The speed is changing its direction all the time. There
is an acceleration which changes the direction of the speed – that is called
centripetal acceleration. Only uniform linear motions are considered to have no
acceleration.
This is the general formula for acceleration
a = dv/dt
When calculating dv, you should keep in mind the change
in the velocity vector’s direction. You can easily see in a graph that with dt
tending to 0 (so the length of the arc covered is also tending to 0), the difference
between vectors Vf and V0 has a direction which is perpendicular to velocity
(the shorter the arc, the closest the angle is to 90 degrees).
There is a formula (which can be deducted from the
previous formula) which allows you to calculate the acceleration:
a = v^2/r
Let’s talk about the units:
v is in m/s
r is in m
so v^2/r
is in (m/s)^2/m = (m^2/s^2)/m = m/s^2
which is the same unit as dv/dt:
dv/dt = (m/s)/s= m/s^2
Answer:
1,780,000 N
Explanation:
0.2 atm × (1.013×10⁵ Pa/atm) = 20,260 Pa
Force = pressure × area
F = 20,260 Pa × (3.89 m × 22.6 m)
F = 1,780,000 N
12.8 rad
Explanation:
The angular displacement
through which the wheel turned can be determined from the equation below:
(1)
where
![\omega_0 = 0](https://tex.z-dn.net/?f=%5Comega_0%20%3D%200)
![\omega = 34.7\:\text{rad/s}](https://tex.z-dn.net/?f=%5Comega%20%3D%2034.7%5C%3A%5Ctext%7Brad%2Fs%7D)
![\alpha = 47.0\:\text{rad/s}^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%2047.0%5C%3A%5Ctext%7Brad%2Fs%7D%5E2)
Using these values, we can solve for
from Eqn(1) as follows:
![2\alpha\theta = \omega^2 - \omega_0^2](https://tex.z-dn.net/?f=2%5Calpha%5Ctheta%20%3D%20%5Comega%5E2%20-%20%5Comega_0%5E2)
or
![\theta = \dfrac{\omega^2 - \omega_0^2}{2\alpha}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cdfrac%7B%5Comega%5E2%20-%20%5Comega_0%5E2%7D%7B2%5Calpha%7D)
![\:\:\:\:= \dfrac{(34.7\:\text{rad/s})^2 - 0}{2(47.0\:\text{rad/s}^2)}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%3D%20%5Cdfrac%7B%2834.7%5C%3A%5Ctext%7Brad%2Fs%7D%29%5E2%20-%200%7D%7B2%2847.0%5C%3A%5Ctext%7Brad%2Fs%7D%5E2%29%7D)
![\:\:\:\:= 12.8\:\text{rad}](https://tex.z-dn.net/?f=%5C%3A%5C%3A%5C%3A%5C%3A%3D%2012.8%5C%3A%5Ctext%7Brad%7D)
Answer:
His average speed is 45000