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choli [55]
3 years ago
5

Holly measures the mass and the volume of metal block. Given this information, what can Holly calculate about the block?

Physics
2 answers:
Julli [10]3 years ago
6 0
You can calculate the mass by multiplying the density with the volume. So if you know the volume and the mass. You can calculate the density by doing mass ÷ volume
natima [27]3 years ago
6 0

<u>Answer:</u> Holly can calculate the density of the block for the given information.

<u>Explanation:</u>

For the given options:

  • <u>Option A:</u> Acceleration

Acceleration is defined as the rate of change of velocity with respect to time. S.I. unit of acceleration is m/s^2 The equation used to calculate acceleration is:

a=\frac{v}{t}

  • <u>Option b:</u> Density

Density of an object is defined as the ratio of its mass and volume. The chemical equation representing density of an object is:  

\text{Density of object}=\frac{\text{Mass of object}}{\text{Volume of object}}

  • <u>Option c:</u> Force

Force is defined as the push or pull on an object with some mass that causes change in its velocity.

It is also defined as the mass multiplied by the acceleration of the object.

Mathematically,

F=ma

  • <u>Option d:</u> Velocity

Velocity is defined as the rate of change of position with respect to time. The equation used to calculate velocity is:

v=\frac{d}{t}

Hence, Holly can calculate the density of the block for the given information.

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Lerok [7]

Answer:

<h2>The potential difference is 60mV</h2>

Explanation:

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Given data

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\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Ohms Law,

According to the Ohms law,

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so here given as, V = 240 V, I = 32 A,

so we get as, R = 240/32

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7 0
3 years ago
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
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To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

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In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

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The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

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\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

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7 0
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