Question

A ball is thrown straight upward with a speed of 36 m/s. How long does it take to return to its starting point, assuming negligible air resistance?

Answer 1

Answer:

The time taken for the ball to return to the starting point is is 7.4 s

Explanation:

Given;

initial velocity of the ball, u = 36 m/s

the final vellocity at maximum height, v = 0

let time taken for the ball to reach maxmimum height = t

Time taken for the ball to return to the starting point is known as time of flight, calculated as;

$t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}$

T = (2 x 36) / 9.8

T = 7.4 s

Therefore, the time taken for the ball to return to the starting point is is 7.4 s