The first opiton is the answer A)<span>Rahul’s weight
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Answer:
B) 100 J
Explanation:
Assuming the distance given is measured along the incline, the vertical change in height is (5 m)(sin 30°) = 2.5 m. Then the change in potential energy is ...
∆PE = mg(∆h) = (4 kg)(10 m/s^2)(2.5 m) = 100 J
Answer:
Acceleration, 
Explanation:
Given that,
Mass of the planet Krypton, 
Radius of the planet Krypton, 
Value of gravitational constant, 
To find,
The acceleration of an object in free fall near the surface of Krypton.
Solution,
The relation for the acceleration of the object is given by the below formula as :



So, the value of acceleration of an object in free fall near the surface of Krypton is 