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dybincka [34]
3 years ago
9

0.06 0.16 0.6 0.66 least to greastest

Mathematics
1 answer:
Komok [63]3 years ago
7 0
Stack them all up in a row:

0.06
0.16
0.60
0.66

Now order them from least to greatest by each place

0.06, 0.16, 0.60, 0.66

(LOL, you TYPED them least to greatest!)

<span>Hope I helped! (Pick me as brainliest!)</span>
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A set of equations is given below:
nexus9112 [7]

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A pumpkin weighs 31 1/3. It is split into 3 equal pieces. What does each part weigh?
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​​​​​​Write an equation to describe this situation using decimals. “Tessa bought x pounds of almonds. Lark (y) bought more than
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Answer:

y = 1.6x

Step-by-step explanation:

y is the total amount/pounds of almonds that Lark bought. x is the amount that Tessa bought. 3/5 is the same as 0.6. If we multiplied Tessa's amount by 0.6 it would decrease by 2/5 so we have to add 1 to make it 1.6. To find how much Lark bought multiply 1.6 and Tessa's amount.

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rusak2 [61]

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Step-by-step explanation:

5 0
3 years ago
A fence is to be built to enclose a rectangular area of 320 square feet. The fence along three sides is to be made of material t
sergeinik [125]

The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft

<h3>How to maximize area?</h3>

Let the length of the rectangular area be x feet

Let the width of the area = y feet

Area of the rectangle = xy square feet

Or xy = 320 square feet

y = 320/x  -----(1)

Cost to fence the three sides = $6 per foot

Therefore cost to fence one length and two width of the rectangular area

= 6(x + 2y)

Similarly cost to fence the fourth side = $13 per foot

So, the cost of the remaining length = 13x

Total cost to fence = 6(x + 2y) + 13x

Cost (C) = 6(x + 2y) + 13x

C = 6x + 12y + 13x

C  = 19x + 12y

From equation (1),

C = 19x + 12(320/x)

C' = 19 - 3840/x²

At C' = 0, we have;

19 - 3840/x² = 0

19 = 3840/x²

19x² = 3840

x² = 3840/19

x = √(3840/19)

x = 14.22 ft

y = 320/14.22

y = 22.5 ft

Read more about Maximization of Area at; brainly.com/question/13869651

#SPJ1

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