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3 years ago

14

On Sunday a local hamburger shop sold a combined total of 312 hamburgers and cheeseburgers the number of Cheeburger Cheeburger s

old what is two times the number of hamburger sold how many hamburgers were sold on Sunday

1 answer:

Morgarella [4.7K]3 years ago

7 0

624 because thats why i used a caculater. your welcom,e

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I NEED HELP ASAP:

olga55 [171]

First, you have to do some factorization

60 = {1,2,3,4,5,6,10,12,15,20,30,60}
72 = {1,2,3,4,6,8,9,12,18,24,36,72}

the GCF is 12

now we find the number that you multiply by 12 to get 60 and another number to get 72.

12 x 5 = 60
12 x 6 = 72

now we notice if you add 60 + 72, we can now tell that it also equals (12)(5)+(12)(6)= 12(5+6)

6 0

4 years ago

Q1 Express in the form 1.0<br> 4:12

kherson [118]

Answer:

Step-by-step explanation:

4:12= 1:3

3 0

3 years ago

A sofa is on sale for $703 which is 24% less than the regular price what is the regular price

Firdavs [7]

Hello!

We could write this as an equation below.

0.76x=703

We divide both sides by 0.76.

x=925

Therefore, the regular price is $925.

I hope this helps!

5 0

3 years ago

Read 2 more answers

The quotient of fifteen and the product of two times x

snow_lady [41]

30 just multiply 15 times 2 your welcome

8 0

4 years ago

If the basalt at the top of the ancient valley below Vulcan's Throne yields a radiometric date (K-Ar) of 15,000 years, and the l

zepelin [54]

Answer:

$1.69\times 10^3$ feet/million year

Step-by-step explanation:

We are given that

Elevation of top of basalt in valley =4100 feet

Elevation of bottom of basalt in valley =2100 feet

Age of top of basalt in valley=15000 years

Age of bottom of basalt in valley=1.2 million years= $1.2\times 10^6 years=1200000 years$

We have to find the rate of basalt filling in the valley in feet per million yeas

Rate of basalt filling in the valley= $\frac{Elevation\;of\;top\;of\;basalt\;in\;valley-elevation\;of\;bottom\;of\;basalt\;in\;valley}{age\;of\;bottom\;of\;basalt\;in\;valley-age\;of\;top\;of\;basalt\;in\;valley}$

Rate of basalt filling in the valley= $\frac{4100-2100}{1200000-15000}=\frac{2000}{1185000}=1.69\times 10^{-3} feet/year$

Rate of basalt filling in the valley= $1.69\times 10^{-3}\times 10^{6}=1.69\times 10^3$ feet/million year

6 0

4 years ago