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vlabodo [156]
4 years ago
6

40 sweater to 33% discount

Mathematics
2 answers:
Snowcat [4.5K]4 years ago
7 0

Answer:

$13.20

Step-by-step explanation:

40 x 0.33 = 13.2

Vitek1552 [10]4 years ago
4 0
The sweater will be 26.80 dollars
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Melissa has reached her credit card limit of $6,500. Since Melissa has poor credit history, the annual interest rate on her cred
GrogVix [38]
You my 220+235 and then you get the Nader
4 0
3 years ago
I need help with 1-3 please and help!
Ghella [55]

Answer:

Q : 3

10x - 11 = 120 - 11 = 109°

 3x - 2    = 36 - 2  = 34°

 3x + 1     = 36 + 1  = 37°

Q ; 2

3x - 5 = 27 - 5= 22°

7x + 5 = 63 + 5 = 68°

And 90°

Q1 :

∠1 = 92°

∠2 = 42°

∠3 =  113°

Step-by-step explanation:

Solution for Q : 3

As the angle of all three is given as ,

10x - 11

3x - 2

3x + 1

We know sum of all the three angles of triangle = 180 °

So, (10x - 11) + (3x - 2) + (3x + 1) = 180°

Or,   16x - 12 = 180°

Or     16x = 192°, So    , x = 12

So, all three angles are 10x - 11 = 120 - 11 = 109°

                                       3x - 2    = 36 - 2  = 34°

                                       3x + 1     = 36 + 1  = 37°

Solution for Q - 2

Given angles are

3x - 5

7x + 5

90°

We know sum of all the three angles of triangle = 180 °

so ,(3x - 5) + (7x + 5) + 90 = 180°

or 10x  =                       180 - 90 = 90°

SO, x = 9°

SO, all the three angles are 3x - 5 = 27 - 5= 22°

                                              7x + 5 = 63 + 5 = 68°

And                                                                    90°

Solution for Q : 1

From,

the shown fig it is clear that

The ∠2 = 42°      (<u> opposite vertical angles</u> )

so, in  left triangle

50° + ∠2 + ∠1  = 180°

Or,  50° + 42° + ∠1 = 180°     ( sum of all angles of triangles = 180°)

Or, ∠1 = 92°

 Again

From right figure triangle

∠2 + 25° + ∠3 = 180°

Or, 42° + 25° + ∠3 = 180

Or, ∠3 = 113°

3 0
3 years ago
If sin theta = 2/5 and theta is in quadrant I, determine the following.
anzhelika [568]

\bf sin(\theta )=\cfrac{\stackrel{opposite}{2}}{\stackrel{hypotenuse}{5}}\impliedby \textit{let's find the \underline{adjacent side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=\stackrel{hypotenuse}{5}\\ a=adjacent\\ b=\stackrel{opposite}{2}\\ \end{cases} \\\\\\ \pm\sqrt{5^2-2^2}=a\implies \pm\sqrt{21}=a\implies \stackrel{I~Quadrant}{+\sqrt{21}=a}


recall that cosine is positive on the I Quadrant, so though we get a ± valid roots, only the positive one applies.


\bf cos(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{hypotenuse}{5}} \\\\\\ tan(\theta)=\cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}} \qquad \qquad cot(\theta)=\cfrac{\stackrel{adjacent}{\sqrt{21}}}{\stackrel{opposite}{2}} \\\\\\ csc(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{opposite}{2}} \qquad \qquad sec(\theta)=\cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}


now, for tangent and secant, let's rationalize the denominator.


\bf tan(\theta)\implies \cfrac{\stackrel{opposite}{2}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{2\sqrt{21}}{21} \\\\\\ sec(\theta)\implies \cfrac{\stackrel{hypotenuse}{5}}{\stackrel{adjacent}{\sqrt{21}}}\cdot \cfrac{\sqrt{21}}{\sqrt{21}}\implies \cfrac{5\sqrt{21}}{21}

5 0
3 years ago
Find (f-g)(x) when f(x)=3x+2 g(x)=2x^2-4 h(x)=x^2-x+7
Ad libitum [116K]
(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6
7 0
3 years ago
The credit remaining on a phone card (in dollars) is a linear function of the total calling time made with the card (in minutes)
SCORPION-xisa [38]

Answer:

The credit remaining on a phone card (in dollars) is a linear function of the

total calling time made with the card (in minutes), as shown in the figure below.

The remaining credit after 45 minutes of calls is $22.80 , and the remaining

credit after 64 minutes of calls is $19.76.

Step-by-step explanation:

What is the remaining credit after 73 minutes of calls?

;

Not sure what figure you are referring to, write an equation from the given values:

Assign the values as follows

x1 = 45; y1 = 22.80

x2 = 64; y2 = 19.76

:

Find the slope (m) using the formula: m = %28y2-y1%29%2F%28x2-x1%29

m = %2819.76-22.80%29%2F%2864-45%29 = %28-3.04%29%2F%2819%29

m = -.16

:

7 0
3 years ago
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