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viktelen [127]
3 years ago
5

Is the ordered pair a solution to the system of linear equations? Select Yes or No. Yes No Ordered pair: ​(−2,2)(−2,2)​ System o

f equations: ​−7x+2y=06x+6y=0−7x+2y=06x+6y=0​
Mathematics
2 answers:
AleksAgata [21]3 years ago
6 0
The solution of a system of linear equations is an ordered pair that satisfies ALL the equations in the system.
Darya [45]3 years ago
5 0
Youyou havehave aa problemproblem withwith typingtyping doubledouble


if it is a solution, it makes both statements when subsituted
(x,y)
(-2,2)
x=-2, y=2
for
-7x+2y=0 or
6x+6y=0

-7(-2)+2(2)=0 or
6(-2)+6(2)=0

14+4=0 or
-12+12=0

18=0 or
0=0

2nd one is true, but not first

the solution would be
6x+6y=0, so x=-y, then 7y+2y=0, then y=0, then x=0
soltuion would be (0,0)

(-2,2) is not a solution that sastifies both equation simultaneously
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Answer:

angle 1 = 76 degrees

Step-by-step explanation:

2 angles side by side on a straight line should equal 180 degrees.

angle 1 + 104 = 180

angle 1 = 76

6 0
4 years ago
Perform the indicated operation g(x)=-x-3 h(x) = x 2+X Find (goh) (x)​
Klio2033 [76]

Answer:

(g\circ h)(x)=-x^2-x-3

Step-by-step explanation:

So we have the two functions:

g(x)=-x-3\text{ and } h(x)=x^2+x

And we want to find:

(g\circ h)(x)

This is the same thing as:

=g(h(x))

So, substitute h(x) into g(x):

g(x)=-x-3\\g(h(x))=-(x^2+x)-3

Distribute the negative:

g(h(x))=-x^2-x-3

And we're done!

So:

(g\circ h)(x)=-x^2-x-3

6 0
3 years ago
Read 2 more answers
I have homework for tomorrow can someone help
Tema [17]

Answer:

x = 42 degrees.

Step-by-step explanation:

We see a cyclic quadrilateral, so by the cyclic quadrilateral theorem we notice that the angle marked with x degrees is equal to the angle marked with 42 degrees. Hence, x = 42 degrees.

3 0
3 years ago
A peregrine falcon can fly 322 kilometers per hour. How many meters per hour can the falcon fly
lianna [129]
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That is the relationship between km and m
Because we are turning bigger units into smaller we the number will increase.

example   2 wks = 14 days  two became 14 - it increased
7 0
3 years ago
Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that th
11111nata11111 [884]

Answer:

The null hypothesis is H_0: \mu = 14

The alternate hypothesis is H_a: \mu < 14

The test statistic is t = -1.95.

The p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

Step-by-step explanation:

Suppose a consumer product researcher wanted to find out whether a highlighter lasted less than the manufacturer's claim that their highlighters could write continuously for 14 hours.

At the null hypothesis, we test if the mean is 14 hours, that is:

H_0: \mu = 14

At the alternate hypothesis, we test if the mean is less than 14 hours, that is:

H_a: \mu < 14

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

14 is tested at the null hypothesis:

This means that \mu = 14

X = 13.6 hours, s = 1.3 hours. Sample of 40:

In addition to the values of X and s given, we have that n = 40

Test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{13.6 - 14}{\frac{1.3}{\sqrt{40}}}

t = -1.95

The test statistic is t = -1.95.

P-value:

The p-value of the test is the probability of finding a sample mean lower than 13.6, which is a left tailed test, with t = -1.95 and 40 - 1 = 39 degrees of freedom.

Using a calculator, the p-value is of 0.0292. This means that for a level of significance of 0.0292 and higher, there is sufficient evidence to conclude that the  highlighters wrote for less than 14 continuous hours.

5 0
3 years ago
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