W^-3
(4)^-3 = 1/(4)^3
1/64.
The solution is 1/64.
Answer:
<em>The second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>
Step-by-step explanation:
We can't confirm the length of these diagonals based on the appearance of the figure, so let us apply Pythagorean Theorem;
This diagonal divides each figure ( square + rectangle ) into two congruent, right angle triangles ⇒ from which we may apply Pythagorean Theorem, where the diagonal acts as the hypotenuse;
5^2 + 5^2 = x^2 ⇒ x is the length of the diagonal,
25 + 25 = x^2,
x^2 = 50,
x = √50
Now the same procedure can be applied to this other quadrilateral;
3^2 + 7^2 = x^2 ⇒ x is the length of the diagonal,
9 + 49 = x^2,
x^2 = 58,
x = √58
<em>Therefore the second figure ( rectangle ) has a longer length of it's diagonal comparative to the first figure ( square )</em>
Okay its 797,619,000,132
They all have different place values
<h3>
<u>Explanation</u><u>:</u></h3>
- Calculate the slope with two given coordinate points by using rise over run.

Let these points



Substitute the value of m in the equation.

- Substitute any coordinate points that are given or part of the graph in the equation.


- Solve the equation for b-term.

- Rewrite the equation by substituting the value of b in the equation.

<h3>
<u>Answer</u></h3>

<em>If</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>any</em><em> </em><em>questions</em><em> </em><em>related</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>answer</em><em>,</em><em> </em><em>feel</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em> </em><em>via</em><em> </em><em>comment</em><em>.</em>
3=4m+ b
-1=3m+b
m=4
plug in to either equation,
3=16+ b
b=-13
Thus, C would be the answer.