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3 years ago

A verbal phrase in a word problem that is a keyword for subtraction.

1 answer:

4 0

In a word problem, you need to be able to interpret words into mathematical symbols or algebraic expressions, focusing on keywords that specify the mathematical procedures required to solve the problem with both the operation and the order of the expression. Here are some examples of verbal phrase for subtraction.

<span>Deduct, decrease by, difference, left over, less than, minus, reduce, remains, remove, subtract and take away.</span>

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What percent of 30 is 33

Llana [10]

Hi!

To solve this we can set up a proportion and cross multiply.

$\frac{33}{30} \frac{x}{100}$

33 x 100 = 3300
3300/30 = 110

The answer is 110%

Hope this helps! :)

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3 years ago

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fgiga [73]

Answer:

A. 7 pounds

B. $1.60

Step-by-step explanation:

For A you Divide 21 by 3

For B you Divide 14 by 9

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3 years ago

Read 2 more answers

If y= 17 inches , x= 19 inches , and h=9 inches , what is the area of the object ?

mr Goodwill [35]

Step-by-step explanation:

brainly.com/question/12448502

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3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is