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MArishka [77]
3 years ago
5

Please help!!! 20 POINTS!!

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0

Answer:

it would be 9 by 6

Step-by-steit would be 9 by 6p explanation:

it would be 9 by 6

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Help me ASAP please really quick it’s my last question <br><br> Find the area of this please
adell [148]
The answer to this equation is 13ft squared
8 0
3 years ago
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If y=6 When x=10,find x when y=18
erik [133]
X=22 because if y=6 and x=10 so 6+4=10 so 18+4=22
5 0
4 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
A middle school has the fifth and sixth grades. There are 100 fifth-grade boys and 110 fifth-grade girls. There are 7 fewer sixt
Mama L [17]

The ratio of girls to boys in the middle school = 213 : 193

Number of fifth-grade boys = 100

Number of fifth grade girls = 110

There are 7 fewer sixth-grade boys than fifth-grade boys

Number of sixth-grade boys = 100 - 7

Number of sixth-grade boys = 93

There are 10 more sixth-grade girls than sixth-grade boys

Number of sixth-grade girls = 93 + 10

Number of sixth-grade girls = 103

Total number of girls = Number of sixth-grade girls + Number of fifth-grade girls

Total number of girls = `103 + 110

Total number of girls = 213

Total number of boys = Number of sixth-grade boys + Number of fifth-grade boys

Total number of boys = `93 + 100

Total number of boys = 193

The ratio of girls to boys in the middle school = 213 : 193

Learn more on ratio here: brainly.com/question/25927869

4 0
3 years ago
Translation of a 2D shape..<br> Due in tomorrow, please help! Xx
bazaltina [42]
(5,7) (5,4) (7,4) hope that helps
4 0
4 years ago
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