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3 years ago

9

Gabriela walked to a toy store around noon and , after browsing for 2222 minutes, decided to buy a race car for $9.22. Gabriela

handed the salesperson $9.22 for her purchase.
How much change did Gabriela receive?

1 answer:

Yanka [14]3 years ago

5 0

No change. She gave the salesperson exactly the right amount to buy the racecar.

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What is the slope of all lines parallel to the line 4x-5y+-1?

Bond [772]

Given equation of the line ,

$\implies 4x - 5y +(-1) = 0$

Simplify ,

$\implies 4x - 5y - 1 = 0$

Transpose terms to RHS ,

$\implies 5y = 4x - 1$

Divide both sides by 5 ,

$\implies \boxed{ y =\dfrac{4}{5}x -\dfrac{1}{5}}$

Now we know the slope intercept form of the line as $y = mx + c$ we have ,

$m =\dfrac{4}{5}$

As we know that the slope of all parallel lines are same . Henceforth ,

$m_{|| \ lines } =\dfrac{4}{5}$

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3 years ago

The CEO of a software company is committed to expanding the proportion of highly qualified women in the organization’s staff of

pishuonlain [190]

Answer:

Null Hypothesis, $H_0$ : p $\geq$ 45%

Alternate Hypothesis, $H_A$ : p < 45%

Step-by-step explanation:

We are given that the proportion of women in similar sales positions across the country in 2004 is less than 45%.

The collected random sample of size 50 showed that only 18 were women.

<u><em>Let p = proportion of women in similar sales positions across the country in 2004</em></u>

So, Null Hypothesis, $H_0$ : p $\geq$ 45%

Alternate Hypothesis, $H_A$ : p < 45%

Here, <u><em>null hypothesis states that</em></u> the proportion of women in similar sales positions across the country in 2004 is more than or equal to 45%.

On the other hand, <u><em>alternate hypothesis states that</em></u> the proportion of women in similar sales positions across the country in 2004 is less than 45%.

The test statistics that would be used here is One-sample z proportion test statistics, i.e;

T.S. = $\frac{\hat p -p}{\sqrt{\frac{\hta p(1-\hat p)}{n} } }$ ~ N(0,1)

Hence, the above hypothesis is appropriate for the given situation.

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3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

<u>━━━━━━━━━━━━━━━━━━━━</u>

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3 years ago

Read 2 more answers

A case holds 48 boxes of candy and costs $24. How much would 2 % cases of candy cost?

Tatiana [17]

Answer:

48 cents

Step-by-step explanation:

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3 years ago

suppose you are standing on one bank of the river. A tree on the other side of the river is known to be 150ft tall. A line from

Eva8 [605]

You can use trigonometry and the tangent to get:
tan(11°)=150/x
so x=772 ft

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3 years ago