Question

Consider the following mechanism.

Answer 1

Answer :

(a) The overall equation is:

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

(b) The intermediates are  :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$

Explanation :

Part (a) :

(1) $ClO^-(aq)+H_2O(l)\rightarrow HClO(aq)+OH^-(aq)$   (fast)

(2) $I^-(aq)+HClO(aq)\rightarrow HIO(aq)+Cl^-(aq)$    (slow)

(3) $OH^-(aq)+HIO(aq)\rightarrow H_2O(l)+IO^-(aq)$   (fast)

By adding the three equations and cancelling the common terms on both side, we will get the overall equation.

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

Part (b)  :

Intermediates are generated and consumed in the mechanism and do not include in the overall equation.

Since, intermediates will not include in the overall mechanism.

The intermediates are  :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$