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Pepsi [2]
3 years ago
8

Consider the following mechanism.

Chemistry
1 answer:
solong [7]3 years ago
7 0

Answer :

(a) The overall equation is:

ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)

(b) The intermediates are  :

OH^-(aq),HClO(aq)\text{ and }HIO(aq)

Explanation :

<u>Part (a) :</u>

(1) ClO^-(aq)+H_2O(l)\rightarrow HClO(aq)+OH^-(aq)   (fast)

(2) I^-(aq)+HClO(aq)\rightarrow HIO(aq)+Cl^-(aq)    (slow)

(3) OH^-(aq)+HIO(aq)\rightarrow H_2O(l)+IO^-(aq)   (fast)

By adding the three equations and cancelling the common terms on both side, we will get the overall equation.

ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)

<u>Part (b)  :</u>

Intermediates are generated and consumed in the mechanism and do not include in the overall equation.

Since, intermediates will not include in the overall mechanism.

The intermediates are  :

OH^-(aq),HClO(aq)\text{ and }HIO(aq)

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ΔG o for the reaction H2(g) + I2(g) ⇌ 2HI(g) is 2.60 kJ/mol at 25°C. Calculate ΔG o , and predict the direction in which the rea
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The reaction is not spontaneous in the forward direction, but in the reverse direction.

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<u>Step 1: </u>Data given

H2(g) + I2(g) ⇌ 2HI(g)     ΔG° = 2.60 kJ/mol

Temperature = 25°C = 25+273 = 298 Kelvin

The initial pressures are:

pH2 = 3.10 atm

pI2 = 1.5 atm

pHI 1.75 atm

<u>Step 2</u>: Calculate ΔG

ΔG = ΔG° + RTln Q  

with ΔG° = 2.60 kJ/mol

with R = 8.3145 J/K*mol

with T = 298 Kelvin

Q = the reaction quotient → has the same expression as equilibrium constant → in this case Kp = [p(HI)]²/ [p(H2)] [p(I2)]

with pH2 = 3.10 atm

pI2 = 1.5 atm

pHI 1.75 atm

Q = (3.10²)/(1.5*1.75)

Q = 3.661

ΔG = ΔG° + RTln Q  

ΔG = 2600 J/mol + 8.3145 J/K*mol * 298 K * ln(3.661)  

ΔG =5815.43 J/mol = 5.815 kJ/mol

To be spontaneous, ΔG should be <0.

ΔG >>0 so the reaction is not spontaneous in the forward direction, but in the reverse direction.

4 0
3 years ago
A gallon of water has a mass of 3.79 kg. how many moles of water (18.02 g/mol) is this?
garik1379 [7]
First, we will convert the mass of the gallon to grams:
a gallon of water has a mass of 3.79 * 1000 = 3790 grams of water

number of moles can be calculated using the following rule:
number of moles = mass / molar mass
Therefore,
number of moles = 3790 / 18.02 = 210.32 moles
3 0
3 years ago
Read 2 more answers
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