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3 years ago

Consider the following mechanism.

Chemistry

1 answer:

solong [7]3 years ago

7 0

Answer :

(a) The overall equation is:

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

(b) The intermediates are :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$

Explanation :

Part (a) :

(1) $ClO^-(aq)+H_2O(l)\rightarrow HClO(aq)+OH^-(aq)$ (fast)

(2) $I^-(aq)+HClO(aq)\rightarrow HIO(aq)+Cl^-(aq)$ (slow)

(3) $OH^-(aq)+HIO(aq)\rightarrow H_2O(l)+IO^-(aq)$ (fast)

By adding the three equations and cancelling the common terms on both side, we will get the overall equation.

$ClO^-(aq)+I^-(aq)\rightarrow Cl^-(aq)+IO^-(aq)$

Part (b) :

Intermediates are generated and consumed in the mechanism and do not include in the overall equation.

Since, intermediates will not include in the overall mechanism.

The intermediates are :

$OH^-(aq),HClO(aq)\text{ and }HIO(aq)$

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Volume of carbon dioxide gas evolved at STP by heating 7.3 gram of Mg(Hco3)2 will be

Y_Kistochka [10]

Answer:

1.12dm³

Explanation:

The reaction is a decompositon reaction. It is expressed below:

Mg(HCO₃)₂ + Heat → MgCO₃ + H₂O + CO₂

This is the balanced reaction equation.

We have 1 mole of Mg, 2 mole of H, 2 mole of C, 6 mole of O on both sides of the reaction.

To calculate the volume of CO₂ gas evolved at S.T.P:

We work from the known to the unknown.

The known is Mg(HCO₃)₂ and the unknown is CO₂

1. Find the number of moles of Mg(HCO₃)₂ from the given mass

2. Since we know that chemical reactions obey the law of conservation of mass. The balanced chemical reaction shows that, 1 mole of Mg(HCO₃)₂ would give 1 mole of CO₂

3. We use information from (2) to find the number of moles of CO₂. With the number of moles of CO₂ found, we use the formula below to find the volume evolved at S.T.P

Volume evolved =

number of moles of CO₂ x 22.4dm³mol⁻¹

Solution:

Given/known parameters:

Mass of Mg(HCO₃)₂ = 7.3g

Step 1:

Number of moles

of Mg(HCO₃)₂ = mass/molar mass

Molar mass of Mg(HCO₃)₂ :

Atomic mass of Mg = 24gmol⁻¹

H = 1gmol⁻¹

C = 12gmol⁻¹

O = 16gmol⁻¹

Molar Mass Mg(HCO₃)₂

= [24 + 2{1 + 12 + (16 x3)} ]

= 24 + 2(1 +12 + 48)

= 24 + 122

= 146gmol⁻¹

Number of moles of

Mg(HCO₃)₂ = 7.3g/126gmol⁻¹ = 0.05mol

Step 2:

We know from the balanced equation that:

1mole of Mg(HCO₃)₂ = 1 mole of CO₂

So: 0.05mol of Mg(HCO₃)₂ = ?

This would also produce 0.05mol of CO₂

Step 3:

Volume of CO₂ evolved =

number of moles of CO₂ x 22.4dm³mol⁻¹

= 0.05 x 22.4

= 1.12dm³

The volume of CO₂ gas evolved at S. T. P is 1.12dm³

8 0

4 years ago

Read 2 more answers

2. How many moles of hydrogen atoms are there in 154 mL of 0.18 M H2SO4? Write your

katrin [286]

2. 0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. 15.2506 heat in Joules is absorbed by 150.0 mL of pure water that is heated from 21.2°C to 45.5°C.

4. 0.75 M is the concentration of Na+ ions in 25.0 mL of 1.50 M NaOH is reacted with 25.0 mL of 1.50 M HCI

Explanation:

Number of moles of H2SO4 can be calculated by the given volume and molarity from the formula:

molarity = $\frac{number of moles}{volume of teh solution}$

number of moles = molarity × volume of the solution of H2SO4

number of moles = 0.18 × 0.154 litres

= 0.02772 moles of H2SO4.

Since 1 mole of H2SO4 contains 2 moles of hydrogen

so, 0.02772 moles of H2SO4 will have x moles

$\frac{1}{2}$ = $\frac{0.0272}{x}$

2 × 0.02772 = x

0.05544 moles of hydrogen atom are present in 154 mL 0.18 M solution of H2SO4.

3. The heat absorbed is calculated from the formula:

ΔH = cp × m × ΔT ( ΔT = change in temperature in Kelvin, m in kg, cp= specific heat of water)

putting the values in formula:

ΔH = 4.184 × 0.15 × ( 318.65-294.35)

= 4.184 × 0.15× 24.3

= 15.2506 Joules of heat is absorbed.

4. The concentration of Na+ ions

the balanced equation is

NaOH + HCl⇒ NaCl + H20

from one mole of NaCl 1 mole of NaCl i.e one 1 mole of Na+ ions is formed.

number of moles of NaOH is calculated by the formula:

Molarity = $\frac{number of moles}{volume of the solution}$

number of moles = 0.025L × 1.50M

= 0.0375 moles of NaOH

so 1 mole of NaOH produces 1 mole of Na= ions

hence, 0.0375 moles produces x moles of Na+ ions

$\frac{1}{1}$ = $\frac{0.0375}{x}$

moles of Na+ is produced.

concentration of NaOH in 50 ml solution because NaOH and HCl of 25 ml reacted.

applying the molarity formula from above

Molarity = $\frac{0.0375}{0.05}$

= 0.75 M

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