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Anuta_ua [19.1K]
1 year ago
13

For which process would the pictured cell be used?

Chemistry
1 answer:
DaniilM [7]1 year ago
3 0

Answer:

Coating a material with metal

(SInce the glasses will be coated with gold.)

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An ethylene glycol solution contains 16.2 g of ethylene glycol (c2h6o2) in 85.4 ml of water. calculate the boiling point of the
Andre45 [30]
<span>Answer: (16.2 g C2H6O2) / (62.0678 g C2H6O2/mol) / (0.0982 kg) = 3.9704 mol/kg = 3.9704 m a.) (3.9704 m) x (1.86 °C/m) = 7.38 °C change 0.00°C - 7.38 °C = - 7.38 °C b.) (3.9704 m) x (0.512 °C/m) = 2.03 °C change 100.00°C + 2.03 °C = 102.03 °C</span>
7 0
3 years ago
Why does the sun appear to be the brightest star in the sky?
skelet666 [1.2K]

Answer:

D

Explanation:

There are only 2 ways to explain this.

distance

and brightness caused by what it is burning.

A is true but it is not the explanation of why it is true.

B this is actually not true. Other stars would burn much more.

C It is not the largest star. In fact it is in the lower middle.

D is the answer. 93 million miles as these things go, is not every much.

3 0
3 years ago
If a pharmacist adds 10 ml of purified water to 30 ml of a solution having a specific gravity of 1.30, calculate the specific gr
xxMikexx [17]

The specific gravity of a sample is the ratio of the density of the sample with respect to one standard sample. The standard sample used in specific gravity calculation is water whose density is 1 g/mL. The solution having specific gravity 1.30 is the density of the sample that is 1.30 g/mL. Thus the weight of the 30 mL sample is (30×1.30) = 39 g.

Now the mass of the 10 mL of water is 10 g as density of water is 10 g/mL. Thus after addition the total mass of the solution is (39 + 10) = 49g and the volume is (30 + 10) = 40 mL. Thus the density of the mixture will be \frac{49}{40}=1.225 g/mL. Thus the specific gravity of the mixed sample will be 1.225 g/mL.

6 0
3 years ago
A child and his mother both have blue eyes. They both have blue eyes because inherited traits of an organism are governed by the
cluponka [151]
The answer would probably be c.
3 0
2 years ago
Read 2 more answers
HELP
tatiyna

Answer:

Bi (Bismuth)

Ag (Silver)

Li (Lithium)

Explanation:

Xe (Xenon) and I (Iodine) are non-metals. They cannot from a metallic bond because metallic bonds are bonds between metals only.

7 0
2 years ago
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