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4 years ago

Find the vertex: -4x² + 16x - 7

Mathematics

1 answer:

guapka [62]4 years ago

7 0

Find the vertex: -4x^2 + 16x - 7

Vertex = ( x, f(x)).

x = -b/2a

x = -16/2(-4)

x = -16/-8

x = 2

f(x) = -4x^2 + 16x - 7

Let x = 2

f(2) = -4(2)^2 + 16(2) - 7

f(2) = -4(4) + 32 - 7

f(2) = -16 + 32 - 7

f(2) = 16 - 7

f(2) = 9

Vertex = (2, 9)

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3 years ago

BD bisects m m Find m

amm1812

The text of the question is not visible in the answering window. I'll reproduce it here:

BD bisects <ABC.

m <ABD= 2.5x + 8.6

m<CBD = 3.5x - 3.4

Find m<ABC

Answer:

$m\angle ABC = 77.2^\circ$

Step-by-step explanation:

We have an angle ABC and a line BD bisecting it.

If an angle is bisected, then the two formed angles are congruent, that is

$m\angle ABD=m\angle CBD$

Substituting the algebraic expressions for both angles:

$2.5x + 8.6=3.5x - 3.4$

Subtracting 8.6 and 3.5x:

$2.5x - 3.5x = -8.6 - 3.4$

Operating:

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$x = 12$

The two angles are:

$m\angle ABD=2.5x + 8.6=2.5(12) + 8.6=38.6^\circ$

$m\angle CBD=3.5x - 3.4 = 38.6^\circ$

As expected, both angles have the same measure.

The measure of the total angle ABC is twice any of those:

$m\angle ABC = 2*38.6^\circ=77.2^\circ$

$\mathbf{m\angle ABC = 77.2^\circ}$

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3 years ago

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3 years ago

Evaluate x6 + y(-9)<br> When x= -2, y = 4

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3 years ago

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Alenkinab [10]

Answer:

$15x-6y=48$

Step-by-step explanation:

So we have the system of equations:

$5x-2y=16\\15x-7y=51$

And we want to multiply the first equation by some constant such that the resulting equation matches the coefficient of [x] in the second equation.

We can see that the coefficient of x in the second equation is 15.

So, to match 15, we must multiply the first equation by 3. So:

$3(5x-2y)=3(16)$

Multiply:

$15x-6y=48$

And we're done!

5 0

3 years ago

Read 2 more answers

Find the vertex: -4x² + 16x - 7​

Find the vertex: -4x² + 16x - 7