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Ksenya-84 [330]
4 years ago
8

Find the vertex: -4x² + 16x - 7​

Mathematics
1 answer:
guapka [62]4 years ago
7 0

Find the vertex: -4x^2 + 16x - 7​

Vertex = ( x, f(x)).

x = -b/2a

x = -16/2(-4)

x = -16/-8

x = 2

f(x) = -4x^2 + 16x - 7

Let x = 2

f(2) = -4(2)^2 + 16(2) - 7

f(2) = -4(4) + 32 - 7

f(2) = -16 + 32 - 7

f(2) = 16 - 7

f(2) = 9

Vertex = (2, 9)

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I got a maths equation which i don't really get how to work out, the question is : solve 4x^2+x-3=0
Maru [420]

The solutions for the given equation 4x^2+x-3=0 are x = -1 and x = 3/4. Using the quadratic formula, the solutions for the given equation are calculated.

<h3>What is the quadratic formula?</h3>

The formula which is used to calculate the roots(solutions) of the quadratic equation in the form ax^2+bx+c=0 is

x = [- b ± \sqrt{b^2-4ac}]/2a

<h3>Calculation:</h3>

The given equation is 4x^2+x-3=0

In comparison with the standard form of quadratic equation ax^2+bx+c=0,

we get, a = 4, b = 1 and c = -3

So, solving the given equation using the quadratic formula,

x = [- b ± \sqrt{b^2-4ac}]/2a

  = [- 1 ± \sqrt{1-4(4)(-3)}]/2(4)

  = [-1 ± \sqrt{49}]/8

  = (-1 ± 7)/8

Thus, x =  (-1 + 7)/8 = 3/4 and x = (-1-7)/8 = -8/8 = -1

Therefore, the solutions of the given equation are x = -1 and x = 3/4.

Learn more about solving quadratic equations here:

brainly.com/question/1214333

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