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ValentinkaMS [17]
4 years ago
11

Trigonometry help. I cant do this

Mathematics
2 answers:
docker41 [41]4 years ago
8 0
 the answer is 0.921.

Apply the trig identity: cos (a + b) = cos a.cos b - sin a.sin b
<span><span>cos<span>(75)</span></span>=<span>cos<span>(30+45)</span></span>=<span>cos30</span>⋅<span>cos45</span>−<span>sin30</span>⋅<span>sin45</span><span>= 

0.921

</span></span>
Drupady [299]4 years ago
3 0
Cos75 = 0.258819045 =  sin15
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What is the answer to y divided by 2 = 17
bija089 [108]
The answer is Y=34
Because 34/17 is 34
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3 years ago
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Write the series using summation notation.<br><br> 4 + 8 + 12 + 16 + 20+ . . . + 80
zhannawk [14.2K]

Answer:

\sum ^{20} _{n \to \11} 4n

Step-by-step explanation:

In order to write the series using the summation notation, first we need to find the nth term of the sequence formed. The sequence generated by the series is an arithmetic sequence as shown;

4, 8, 12, 16, 20...80

The nth term of an arithmetic sequence is expressed as Tn = a +(n-1)d

a is the first term = 4

d is the common difference = 21-8 = 8-4 = 4

n is the number of terms

On substituting, Tn = 4+(n-1)4

Tn = 4+4n-4

Tn = 4n

The nth term of the series is 4n.

Since the last term is 80, L = 4n

80 = 4n

n = 80/4

n = 20

This shows that the total number of terms in the sequence is 20

According to the series given 4 + 8 + 12 + 16 + 20+ . . . + 80 , we are to take the sum of the first 20terms of the sequence. Using summation notation;

4 + 8 + 12 + 16 + 20+ . . . + 80  = \sum ^{20} _{n \to \11} 4n

4 0
3 years ago
What is equivalent to 9^x=27
erma4kov [3.2K]
If you meant to solve for x...

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3 years ago
Suppose that six individuals are interested in taking part in a study relating BMI to a number of health outcomes. The following
posledela

Answer:

a) Mean = 27.65

Median = 27.645

b) Relative Frequency = 33.33%

Step-by-step explanation:

We are given the following data set:

25.78, 21.06, 36.54, 29.51, 18.96, 34.05

a) Mean and Median

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{165.9}{6} = 27.65

Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}

Sorted data: 18.96, 21.06, 25.78, 29.51, 34.05, 36.54

\text{Median} = \displaystyle\frac{25.78 +29.51}{2} = 27.645

b) BMI above 30 is considered obese

Frequency of obese in the given sample = 2

Relative Frequency =

\displaystyle\frac{\text{Frequency of obese}}{\text{Total number}} = \frac{2}{6} = 0.3333 = 33.33\%

5 0
3 years ago
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