What is equivalent to 9^x=27

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

8 0

If you meant to solve for x...

$9^x=27 \\
(3^2)^x=3^3\\
3^{2x}=3^3\\
2x=3\\
x=\dfrac{3}{2}$

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Can someone explain this to me

Lynna [10]

Answer:

$\huge\boxed{\sf tan \ 28 = x / 14}$

Step-by-step explanation:

Since opposite and adjacent is given, we will use tan as trigonometric ratio.

Hence,

opposite = x , adjacent = 14 and $\theta$ = 28

So,

$\sf tan \theta = opposite / adjacent$

tan 28 = x / 14

$\rule[225]{225}{2}$

Hope this helped!

7 0

2 years ago

What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24

german

$\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}$

$=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}$