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kiruha [24]
3 years ago
5

Given the function f(x) = 3x, find the value of f−1(81).

Mathematics
1 answer:
Shalnov [3]3 years ago
4 0
Given the function f (x) = 3x, find the value of f-1 (81).
 For this case, the first thing you should do is rewrite the function.
 We have then:
 y = 3 ^ x
 From here, we clear the value of x:
 log3 (y) = log3 (3 ^ x)
 log3 (y) = x
 Then, we rewrite the function again:
 f (x) ^ - 1 = log3 (x)
 Now, we evaluate the inverse function for x = 81:
 f (81) ^ - 1 = log3 (81)
 f (x) ^ - 1 = 4
 Answer:
 the value of f-1 (81) is: 
 f (x) ^ - 1 = 4
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<u>We are given</u> :

P ( x ) , has a root of multiplicity 2 at x = 2

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Then

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P ( x ) = a (x - 2)²(x + 3)

= a (x² - 4x + 4)(x + 3)

= a [x³ - 4x² + 4x + 3x² - 12x + 12]

P (0) = -8.4

⇔ a [(0)³ - 4(0)² + 4(0) + 3(0)² - 12(0) + 12] = -8.4

⇔ 12 a  = -8.4

⇔  a  = (-8,4) ÷ 12

⇔  a  = -0,7

<u>Conclusion</u> :

P ( x ) = -0.7 (x - 2)²(x + 3)

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