(2-7m^6)^2
rearrange terms:
(2-7m^6)^2
(-7m^6 + 2)^2
expand the squares:
(-7m^6 + 2)^2
(-7m^6 + 2)(-7m^6 + 2)
distribute:
(-7m^6 + 2)(-7m^6 + 2)
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
distribute:
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
49m^12 - 14m^6 + 2(-7^6 +2)
distribute:
49m^12 - 14m^6 + 2(-7^6 +2)
49m^12 - 14m^6 - 14m^6 + 4
combine like terms:
49m^12 - 14m^6 - 14m^6 + 4
49m^12 - 28m^6 + 4
solution:
49m^12 - 28m^6 + 4
please mark brainliest and hope it helps
I hated doing that stuff, it was a pain for me
Answer:
x = 15
Step-by-step explanation:
Substitute: -4/5x + 7 = -5
Rearrange unknown terms to the left side of the equation: -4/5x = -5 - 7
Calculate the sum or difference: -4/5x = -12
Divide both sides of the equation by the coefficient of variable: x = -12 × (-5/4)
Remove the parentheses: x = 12 × 5/4
Cross out the common factor: x = 3 × 5
Calculate the product or quotient: x = 15
So the answer is: x = 15