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3 years ago

What is. the fraction1/5 of 80?

Mathematics

2 answers:

Ksivusya [100]3 years ago

8 0

$\dfrac{1}{5}\cdot 80=16$

Yuliya22 [10]3 years ago

5 0

$\frac{1}{5} \times 80=\frac{80}{5}=\frac{16 \times 5}{5}=16$

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If f(x) = x2 − 3x − 4 and g(x) = x2 + x, what is (f + g)(x)?

Makovka662 [10]

(f + g)(x) = f(x) + g(x) = x² -3x -4+x² +x= 2x² -2x -4

8 0

2 years ago

Find the midpoint of points A(9,9) and B(2,-1)

Sholpan [36]

Answer:

4 11/2

Step-by-step explanation:(X₁, Y₁) is the coordinates of the 1st point and (X₂, Y₂) is the coordinates of the 2nd point.

Using the formula above,.

7 0

2 years ago

Jordan wrote the following description: Three fewer than one four of x is 12. write an equation to represent the description.

tigry1 [53]

The correct way to write this equation is .25x-3=12. The .25 is interchangeable with $\frac{1}{4}$

8 0

3 years ago

Read 2 more answers

The tables represent the functions f(x) and g(x).

dolphi86 [110]

A function assigns the values. The correct option is C, x=-6.

<h3>What is a Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

A.) When the value of x is -12,

f(-12) = 2/3(-12) + 7 = -1

g(-12) = 2(-12) + 15 = -9

B.) When the value of x is -9,

f(-9) = 2/3(-9) + 7 = 1

g(-9) = 2(-9) + 15 = -3

C.) When the value of x is -6,

f(-6) = 2/3(-6) + 7 = 3

g(-6) = 2(-6) + 15 = 3

D.) When the value of x is -3,

f(-9) = 2/3(-3) + 7 = 5

g(-9) = 2(-2) + 15 = 11

Hence, the correct option is C, x=-6.

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brainly.com/question/5245372

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4 0

1 year ago

Question 9 (1 point)

Romashka [77]

Answer:

Step-by-step explanation:

League A League B

151.12 163.25

148 157

26.83 24.93

29 136

136 145

167 178

207 256

League A in ascending order :

26.83 , 29 , 136, 148 , 151.12 , 167,207

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{26.83+29 +136+ 148+ 151.12+ 167+207}{7}\\\\Mean =123.564$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=148

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(26.83-123.564)^2+(29-123.564)^2+.......+(207-123.564)^2}{7}}=63.98$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 26.83 , 29 , 136, 148

n = 4

Q1=82.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 148 , 151.12 , 167,207

n = 4

Q3=159.06

IQR = Q3-Q1=159.06-82.5=76.56

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(82.5-1.5\times 76.56,159.06+1.5\times 76.56)$

(-32.34,273.9)

So, There is no outlier

Maximum = 207

League B in ascending order :

24.93,136,145,157,163.25,178,256

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\\\Mean = \frac{24.93+136+145+157+163.25+178+256}{7}\\\\Mean =151.45$

Median = Mid value of data

n = 7

So, mid value = 4th term

Median=157

Standard deviation= $\sqrt{\frac{\sum(x_i-\bar{x})^2}{n}}$ = $=\sqrt{\frac{(24.93-151.45)^2+(136-151.45)^2+.......+(256-151.45)^2}{7}}=68.42$

To Find Q1

Q1 is the mid value of lower quartile

Lower quartile : 24.93,136,145,157

n = 4

$Median = \frac{\frac{n}{2} \text{th term}+(\frac{n}{2}+1) \text{th term}}{2}\\Median = \frac{\frac{4}{2} \text{th term}+(\frac{4}{2}+1) \text{th term}}{2}\\Median = \frac{2 \text{th term}+3 \text{th term}}{2}\\Median = \frac{136+145}{2}=140.5$

Q1=140.5

To Find Q3

Q3 is the mid value of upper quartile

Upper quartile : 157,163.25,178,256

n = 4

Q3=170.625

IQR = Q3-Q1=170.625-140.5=30.125

To find outlier

(Q1-1.5IQR ,Q3+1.5IQR)

$(140.5-1.5\times 30.125,170.625+1.5\times 30.125)$

(95.3125,215.8125)

24.93 and 256 are outliers

Maximum = 256

5 0

2 years ago