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yuradex [85]
2 years ago
10

  5y(2x−3)=y(x+2)+20 where x=3

Mathematics
2 answers:
grandymaker [24]2 years ago
7 0
5y(2(3)-3)=y(3+2)+20
5y(6-3)=y(5)+20
5y(3)=5y+20
15y=5y+20
10y=20
y=2

Feliz [49]2 years ago
6 0
Here x=3
so, putting 3 instead of x
5y(2(3)-3)=y(3+2)+20 \\ 5y(3)=5y+20 \\ 15y-5y=20 \\ 10y=20 \\ y=20/10=2
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6 0
2 years ago
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Tn  = ar^n-1

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n is the number of terms

r is the common ratio

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a = 6

r = 1/3

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T3 = 6(1/3)^3-1

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T3= 6 * 1/9

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when n = 4

T4 = 6(1/3)^4-1

T4= 6(1/3)^3

T4= 6 * 1/27

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when n = 5

T5 = 6(1/3)^5-1

T5= 6(1/3)^4

T5= 6 * 1/81

T5 = 2/27

when n = 6

T6 = 6(1/3)^6-1

T6= 6(1/3)^5

T6= 6 * 1/243

T6 = 2/81

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6 0
2 years ago
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zhuklara [117]

Answer:

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Step-by-step explanation:

The factors of the given expression are ...

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Which factor is current and which is resistance is not clear. Usually, resistance is referred to using the variable r, so we suppose the expressions are supposed to be ...

  resistance: (2r +5)

  current: (3i +4)

6 0
3 years ago
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