5y(2x−3)=y(x+2)+20 where x=3

Mathematics

2 answers:

grandymaker [24]2 years ago

7 0

5y(2(3)-3)=y(3+2)+20
5y(6-3)=y(5)+20
5y(3)=5y+20
15y=5y+20
10y=20
y=2

Feliz [49]2 years ago

6 0

Here x=3
so, putting 3 instead of x
$5y(2(3)-3)=y(3+2)+20 \\ 5y(3)=5y+20 \\ 15y-5y=20 \\ 10y=20 \\ y=20/10=2$

You might be interested in

Jana has a number cube numbered 1 to 6. She plans to roll the cube 78 times. Predict the number of times Jana will roll a 2.

Natali5045456 [20]

78/6=13 theres not much to it just divide

7 0

2 years ago

An expression is shown below: 2x3y + 18xy − 10x2y − 90y Part A: Rewrite the expression by factoring out the greatest common fact

SCORPION-xisa [38]

Answer:

Part A : 2y( x³ + 9x - 5x² - 45 ), Part B : 2y( x - 5 )( x² + 9 )

Step-by-step explanation:

Part A : Let's break every term down here to their " prime factors ", and see what is common among them,

2x³y + 18xy − 10x²y − 90y -

2x³y = 2 $*$ x³ $*$ y,

18xy = 2 $*$ 3 $*$ 3 $*$ x $*$ y,

− 10x²y = 2 $*$ - 5 $*$ x² $*$ y, - so as you can see for this example I purposely broke down - 10 into 2 and - 5. I could have placed the negative on the 2, but as that value was must likely common among all the terms, I decided to place it on the 5. The same goes for " − 90y. " I placed the negative there on the 5 once more.

− 90y = 2 $*$ - 5 $*$ 3 $*$ 3 $*$ y

The terms common among each term are 2 and y. Therefore, the GCF ( greatest common factor ) is 2x. Let's now factor the expression using this value.

2y( x³ + 9x - 5x² - 45 )

Part B : Let's simply factor this entire expression. Of course starting with the " factored " expression : 2y( x³ + 9x - 5x² - 45 ),

$2y\left(x^3+9x-5x^2-45\right)$ - Factor out " $(x^3+9x-5x^2-45\right))$ " by grouping,