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icang [17]
3 years ago
5

Look at the figure below:

Mathematics
2 answers:
Anika [276]3 years ago
5 0

Answer:

7.2

Step-by-step explanation:

Dmitrij [34]3 years ago
3 0
The answer has to be 10
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If 32% of a number is 64, what is the number?
Verdich [7]

Hey!

------------------------------------------------

Steps To Solve:

~Turn into decimal

32% = 0.32

~Divide

64 / 0.32 = 200

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{200}}

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Hope This Helped! Good Luck!

7 0
3 years ago
Read 2 more answers
The area of a square is 16 cm2. The square is the base of a cube.
choli [55]

the answer is 96 cm ^ 2

16 × 6 =96

3 0
3 years ago
What are the roots of -12x2 + 11x − 3 = 0?
boyakko [2]
This equation is not factor-able, so we can use the quadratic formula.
x=(-11+square root(11^2-4(-12*-3)))/(2*-12)
x=(-11+square root(-23))/(-24)
Since we have the square root of a negative in this equation, there are no real roots for the quadratic.
6 0
3 years ago
Read 2 more answers
Please do this question
crimeas [40]
It would be 16 more 6th graders that are not in either band or orchestra.
  15 6th Graders in band
  9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class

  100 6th Graders in total
 -42 6th Graders in either class
-------
58 6th Graders in neither class
 58-42= 16 more 6th Graders that are not in either class
You're welcome :)

7 0
3 years ago
Please help, performance task: trigonometric identities
AnnZ [28]

The solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<h3>How to solve the trigonometric equations?</h3>

<u>Equation 1: 1 - cos(x) = 2 - 2sin²(x) from (-π, π)</u>

The equation can be split as follows:

y = 1 - cos(x)

y = 2 - 2sin²(x)

Next, we plot the graph of the above equations (see graph 1)

Under the domain interval (-π, π), the curves of the equations intersect at:

(-π/3, 0.5) and (π/3, 0.5)

Hence, the solutions to 1 - cos(x) = 2 - 2sin²(x) from (-π, π) are (-π/3, 0.5) and (π/3, 0.5)

<u>Equation 2: 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π)</u>

The equation can be split as follows:

y = 4cos⁴(x) - 5cos²(x) + 1

y = o

Next, we plot the graph of the above equations (see graph 2)

Under the domain interval [0, 2π), the curves of the equations intersect at:

(π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Hence, the solutions to 4cos⁴(x) - 5cos²(x) + 1 = 0 from [0, 2π) are (π/3, 0), (2π/3, 0), (π, 0), (4π/3, 0) and (5π/3, 0)

Read more about trigonometry equations at:

brainly.com/question/8120556

#SPJ1

4 0
2 years ago
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