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ira [324]
3 years ago
15

A teacher takes a random sample of 100 students enrolled at Springfield High School and asks them their opinions about the food

served in the school cafeteria. The population of students here is __________________.
A. all high school students in the world

B. the 100 students who are asked questions

C. all students enrolled at Springfield High School

D. all high school students in the country
Mathematics
1 answer:
Reil [10]3 years ago
8 0

The answer is C. All students enrolled at Springfield high school.

You might be interested in
What expressions are equivelent to −3(2+7)
ivanzaharov [21]

Answer:

<h2>-3(2 + 7) = -3(9) or -3(2 + 7) = (-3)(2) + (-3)(7)</h2>

Step-by-step explanation:

-3(2+7)\\\\=-3(9)\\=-27\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\=(-3)(2)+(-3)(7)\\=-6-21\\=-27

8 0
3 years ago
Abcdefgh is a regular octagon. M is a point on the line dh. N is a point on the line fm. The line dn and fm are perpendicular. P
Aloiza [94]

ΔFHM and ΔDFP by addition to ΔMOF and ΔPDO respectively gives

ΔHOP and ΔDOF, which are congruent.

Response:

  • ΔFHM ≅ ΔDFP by transitive property of equality

<h3>Methods used to prove that the two triangles are congruent</h3>

Based on the properties of a regular octagon, the diagonals DH and BF

of a regular octagon are perpendicular, and they bisect each other,

given that the length of half the diagonal represent the radius of the

circumscribing circle.

Therefore;

∠NFP ≅ ∠NFP by reflexive property

∠PNF ≅ ∠MOF all right angles are congruent

ΔMOF is similar to ΔPNF by Angle-Angle AA similarity postulate.

∠OMF ≅ ∠DMN by reflexive property

Therefore;

ΔDMN is similar to ΔMOF by AA similarity postulate.

Similarly, we have;

ΔDMN ~ ΔPDO by AA similarity postulate;

Therefore;

ΔPDO is similar to ΔOMF by transitive property

∠ODP ≅ ∠OFM by CASTC, Corresponding Angles of Similar Triangle are Congruent.

OD = OF distance from center to the vertex of a regular octagon are

equal to the radial length of the circumscribing circle and are therefore

equal.

Therefore;

ΔPDO ≅ ΔOMF by Angle-Side-Angle ASA congruency rule

ΔPDO = ΔOMF definition of congruency

  • ΔHOF ≅ ΔDOF by Side-Angle-Side, SAS, congruency rule

ΔHOF = ΔDOF

ΔFHM = ΔHOF - ΔOMF subtraction property

Similarly

ΔDFP = ΔDOF - ΔPDO = ΔHOF - ΔOMF = ΔFHM by substitution property

ΔDFP = ΔFHM

ΔFHM = ΔDFP by symmetric property.

Therefore;


  • <u>ΔFHM ≅ ΔDFP by definition of congruency</u>

Learn more about the properties of a regular octagon here:

brainly.com/question/4503941

3 0
2 years ago
Please help me with this thanks
Ronch [10]

If x = 1, then 3*1 = 3 which when modded with 5, we get 3 as a remainder. In other words, 3/5 = 0 remainder 3. We don't use the quotient at all when it comes to modular arithmetic. All we care about is the remainder.

If x = 2, then 3*2 = 6 which leads to remainder 1 when we divide by 5. Therefore, 3x = 1 (mod 5) when x = 2.

If x = 3, then 3*3 = 9 = 4 (mod 5) because 9/5 = 1 remainder 4.

So 3x = 4 (mod 5) when x = 3.

<h3>The final answer is C) 3</h3>

We don't need to check D since x = 3 is a solution and it's smaller than x = 4.

If you wanted to check x = 4, then 3*4 = 12 = 2 (mod 5) because 12/5 yields a remainder of 2.

7 0
3 years ago
A produce store sold 45 red apples. If the ratio of red apples to green apples sold was 5 : 2, what is the combined amount of re
lisabon 2012 [21]

The ratio of Red Apples to Green Apples is 5:2. The proportion of red apple is 5/7.

The store sold 45 red apples.

So the combined amount of red and green apples sold = No of red apples sold divided by the proportion of red apples = 45/ (5/7) = 63

The combined amount of red and green apples sold is 63 apples.

6 0
3 years ago
(show your work please) There are 3 green balls, 5 red balls, and 2 blue balls in a box. One ball is randomly drawn, replaced an
JulsSmile [24]
B is the answer, because the half of the balls added
7 0
3 years ago
Read 2 more answers
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