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ira [324]
3 years ago
15

A teacher takes a random sample of 100 students enrolled at Springfield High School and asks them their opinions about the food

served in the school cafeteria. The population of students here is __________________.
A. all high school students in the world

B. the 100 students who are asked questions

C. all students enrolled at Springfield High School

D. all high school students in the country
Mathematics
1 answer:
Reil [10]3 years ago
8 0

The answer is C. All students enrolled at Springfield high school.

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Mercury has a density of 13.6 g/cm^3 . What volume of mercury will have a mass of 47 grams? It’d be very helpful if someone coul
kondaur [170]

Density = mass / volume

Givens

Density = 13.6 grams / cm^3

mass = 47 grams.

Solve

D = m/v

13.6 = 47 / volume Multiply by volume

13.6 * volume = 47 Divide by 13.6

volume = 47 / 13.6

Volume = 3.46 ccs

6 0
3 years ago
6, -12, 24, 8th term of geometric sequence
nordsb [41]

Answer:

a₈ = - 768

Step-by-step explanation:

The nth term of a geometric sequence is

a_{n} = a₁ (r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 6 and r = \frac{a_{2} }{a_{1} } = \frac{-12}{6} = - 2 , then

a₈ = 6 × -2)^{7} = - 6 × - 128 = - 768

5 0
2 years ago
Round to the nearest tenth. I need help ​
puteri [66]

Answer:

118.0

Step-by-step explanation:

using Trigonometry,

x = 99tan(50) \\  = 118.0

4 0
3 years ago
Oint C is on line segment BD‾\overline{BD} BD . Given BD=5x,BD=5x, BD=5x, BC=4x,BC=4x, BC=4x, and CD=4,CD=4, CD=4, determine the
Gennadij [26K]

Answer:

Therefore the required value of \overline{BD} is 20 units.

Step-by-step explanation:

Line Segment: Line segment is a portion of a line whose has two end points.

Given that point C is on the line segment \overline{BD}.

\overline{BD} = 5x , \overline{BC} = 4x and \overline{CD} = 4

C is the point of the line segment of \overline{BD}.

So we can write

\overline {BD}= \overline{BC}+\overline{CD}

Putting the values of \overline{BD}, \overline{BC} and \overline{CD}

5x=4x+ 4

⇒5x-4x= 4

⇒x=4

So we get the value of x.

To get the value of \overline{BD} , we need to put the value of x in the value of \overline{BD}.

Therefore,

\overline{BD} = 5×4

      =20

Therefore the required value of \overline{BD} is 20 units.

3 0
3 years ago
Am trying to simplify the equation 7p³r²-14pr³
gizmo_the_mogwai [7]

Step-by-step explanation:

7p³r² - 14pr³ = 7pr²(p²-2r)

8 0
2 years ago
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