Question

What is the equation of this circle in general form? x2+y2−6x−16=0 x2+y2+6x−16=0 x2+y2−6x+4=0 x² + y² + 6x + 4 = 0

Answer 1

Answer:

x² + y² - 6x - 16 = 0

Step-by-step explanation:

From the graph, the center point is (3, 0) and the radius is 5 so the standard equation is (x - 3)² + y² = 25. Let's turn this into general form now:

x² - 6x + 9 + y² = 25

x² + y² - 6x - 16 = 0

Answer 2

Answer:

$x^2+y^2-6x-16 = 0$

Step-by-step explanation:

Center = (a,b) = (3,0)

So, a = 3 and b = 0

Radius = 5

Now the equation of circle is given by:

=> $(x-a)^2+(y-a)^2 = r^2$

Putting the values, we'll have

=> $(x-3)^2+(y-0)^2= 5^2$

=> $(x-3)^2+y^2=25\\x^2-6x+9+y^2-25 = 0$

=> $x^2+y^2-6x-16 = 0$

So, This is the required generalized form