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Zielflug [23.3K]
2 years ago
9

PLEASE HELP!!!!!!!! ASAP

Mathematics
2 answers:
Varvara68 [4.7K]2 years ago
8 0
Question 1: The areas are equal
Question 2: The area of the circle would be 28.26 cm 2
inessss [21]2 years ago
3 0

Answer: #1) 3. The semicircle has twice the area of the circle

#2) 3. 28.26 cm

Step-by-step explanation:

#1) The formula for area of circle is A=πr².

First, plugging in the radius for the circle, A=π(5)², we get an area of about 78.54 inches².

Plugging in the radius for the semicircle, A=π(10)², which is equal to 314.159.... However, since it is a SEMI-circle, we will divide this value by 2 to give us an area of about 157.08 inches².

Comparing the two areas, we see the semicircle has twice the area of the circle as 78.54 x 2 = 157.08.

#2) Again use the area of circle formula, A=πr². The radius is half the diameter, so half of 6cm=3cm, meaning r=3. plug it in.

A= π(3)²

A= 28.27 cm²

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91 and 1 your welcome bye
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3 years ago
Hector's plant measures 18 inches tall Approximately how many centimeters tall is Hector's plant? (1 in 2.54 cm)
Rufina [12.5K]
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Explanation:
Since there are 2.54 cm in an inch, you do
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6 0
3 years ago
I will mark u as brainliest if u answer this!!
lawyer [7]

i)On z, define a∗b=a−b
here aϵz
+
and bϵz
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i.e.,a and b are positive integers
Let a=2,b=5⇒2∗5=2−5=−3
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i.e., −3∈
/
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hence,∗ is not a binary operation.
ii)On Q,define a∗b=ab−1
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∗ is commutative if,a∗b=b∗a
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∗ is commutative.
Check associative
∗ is associative if (a∗b)∗c=a∗(b∗c)
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a∗(b∗c)=a∗(bc+1)=a(bc+1)+1=abc+a+1
Since (a∗b)∗c

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iii)On Q,define a∗b=
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ab
​

Check commutative
∗ is commutative is a∗b=b∗a
a∗b=
2
ab
​

b∗a=
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ba
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=
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ab
​

a∗b=b∗a∀a,bϵQ
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(a∗b)∗c=
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(
2
ab
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)∗c
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=
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(a∗b)∗c=a∗(b∗c)=
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​
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Since (a∗b)∗c=a∗(b∗c)∀a,b,cϵQ
∗ is an associative binary operation.
iv)On z
+
, define if a∗b=b∗a
a∗b=2
ab

b∗a=2
ba
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Since a∗b=b∗a∀a,b,cϵz
+

∗ is commutative.
Check associative.
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ab
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∗
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2
ab

c
a∗(b∗c)=a∗(2
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Since (a∗b)∗c
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b

a∗b=a
b
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⇒a∗b

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∗ is not commutative.
Check associative
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(a∗b)∗c=a∗(b∗c)
(a∗b)∗c=(a
b
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∗
c=(a
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c

a∗(b∗c)=a∗(2
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a2
bc


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(a∗b)
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c=(2∗3)
∗
4=(2
3
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∗
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4

a∗(b∗c)=2
∗
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Since (a∗b)∗c

=a∗(b∗c)
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vi)On R−{−1}, define a∗b=
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a
​
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∗
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b
a
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+1
​
=
c(b+1)
a
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a∗(b∗c)=a∗(
c+1
b
​
)=
c+1
b
a
​

​
=
b
a(c+1)
​

Since (a∗b)∗c

=a∗(b∗c)
∗ is not a associative binary operation
6 0
3 years ago
What is the place value of 7 in these numbers?
spin [16.1K]

Answer:

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Step-by-step explanation:

I got the answer because ummm thats where i saw the sevens were hehe

3 0
3 years ago
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jonny [76]

Answer:

125

Step-by-step explanation:

5^2 × (15 ÷ 3) = 125

3 0
2 years ago
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