What is the slope of a trend line that passes through the points (5,80) and (7,65)?
1 answer:
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Answer:
60 °F
Step-by-step explanation:
The function can be put into vertex form:
T(x) = 0.264(x² -18x) +81 . . . . factor the leading coefficient from 1st 2 terms
Now, we add the square of half the x-coefficient inside parentheses and subtract the same quantity outside parentheses.
T(x) = 0.264(x² -18x +81) +81 -0.264·81
T(x) = 0.264(x -9)² +59.616
The low temperature for the day was approximately 59.6 °F, which rounds to 60 °F.
Answer:
Step-by-step explanation:
A=b^2+2bh
b = 3
A = 3^2 + 2(3)h
A = 9 + 6h
6h = A - 9