4) The key here is recognizing that the diagonals of a rectangle are congruent, and that they bisect each other. Therefore, AE = BE, and AE + BE = BD. Substituting, you get

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BD=x+75) The sides of a rectangle are parallel to each other. When you draw lines extending the sides, the implications of this become obvious. Suddenly, you have two parallel lines intersected by a transversal, and you probably know those angle relationships. BAC = ACD, so

.

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To find AED (I believe there's an easier way, but I'm not sure), see that AED is the supplement of AEB, and AEB is 180°

. Therefore, AED is

.
AED=52°