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kompoz [17]
3 years ago
5

Can someone PLEASE help me with 4 and 5??? I’m legitimately struggling.

Mathematics
2 answers:
puteri [66]3 years ago
4 0
4) The key here is recognizing that the diagonals of a rectangle are congruent, and that they bisect each other. Therefore, AE = BE, and AE + BE = BD. Substituting, you get (2x+3)+(12-x)=BD \\ x+15=BD.
BD=x+7

5) The sides of a rectangle are parallel to each other. When you draw lines extending the sides, the implications of this become obvious. Suddenly, you have two parallel lines intersected by a transversal, and you probably know those angle relationships. BAC = ACD, so 3x+5=40-2x. x=7.

To find AED (I believe there's an easier way, but I'm not sure), see that AED is the supplement of AEB, and AEB is 180° - 2(BAC) = 180-6x-10 = 170-6(7)=128. Therefore, AED is 180-128=52. 
AED=52°

zzz [600]3 years ago
3 0
Problem 4.

In a rectangle, the diagonals are congruent and bisect each other.
You have AC = BD, and AE = CE = BE = DE.
Also each segment of a diagonal is half the length of the diagonal.

AE = BE

2x + 3 = 12 - x

3x = 9

x = 3

AE = 2x + 3 = 2(3) + 3 = 6 + 3 = 9

BD = 2(AE) = 2(9) = 18

Problem 5.

Sides AB and CD are parallel.
Angles BAC and ACD are alternate interior angles of parallel lines, so they are congruent.

m<BAC = m<ACD

3x + 5 = 40 - 2x

5x = 35

x = 7

m<ACD = 40 - 2x = 40 - 2(7) = 40 - 14 = 26

m<BDC = m<ACD = 26

<AED is a remote exterior angle to angles BDC and ACD.

m<AED = m<BCD + m<ACD = 26 + 26 = 52
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Pls solve this qn..............ASAP<br> PLS DON'T SPAMMMMM!!
Anni [7]

Probability ( a flowering plant or fruit plant) is  \frac{13}{30} and Probability (neem plant or peepal plant) is  \frac{29}{60}.

Step-by-step explanation:

Given,

Number of neem plant = 125

Number of peepal plant = 165

Number of creppers plant = 50

Number of fruit plant = 150

Number of flowering plant = 110

To find the probability ( a flowering plant or fruit plant)

and probability ( neem or peepal)

Formula

P( A or B) = P(A) + P(B)

Probability ( a flowering plant or fruit plant) = \frac{110}{600} + \frac{150}{600}

= \frac{260}{600} = \frac{13}{30}

And,

Probability (neem plant or peepal plant) = \frac{125}{600} +\frac{165}{600}

= \frac{290}{600} = \frac{29}{60}

4 0
3 years ago
Given a standard deck of 52 cards, 3 cards are dealt without replacement. Using this situation, answer the questions below.&lt;b
kherson [118]
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.

Part A:

There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.

Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17

Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.

Therefore, the probability that <span>all three cards are queens is given by

\frac{1}{13} \times \frac{1}{17} \times \frac{1}{25} = \frac{1}{5525}



Part B:

Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.



Part C:

Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.

Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17



Part D:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.

Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04



Part E:

<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.

Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
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liubo4ka [24]

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lapo4ka [179]

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3 0
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