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tiny-mole [99]
3 years ago
15

A horse might drink 50L, a sheep might drink 4L and a chicken might drink 200ML. How much water would a farm with 3 horses, 15 s

heep, and 12 chickens need for a day?
Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
5 0
50L x 3 = 150. 4L x 15 = 60. 0.2L x 12 = 2.4. 150 + 60 + 2.4 = 212.4L.
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4 0
3 years ago
According to the rational root theorem, what are all the potential rational roots of f(x)= 5x^3-7x+11
Tems11 [23]

The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.

In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.

So, the only feasible solutions are

\pm\dfrac{11}{5},\quad\pm 11,\quad \pm\dfrac{1}{5}, \pm 1

For the record, in this case, none of the feasible solutions are actually a root of the polynomial.

8 0
2 years ago
Oranges sell 8 for $1.84. Find the unit rate.
sweet-ann [11.9K]

Step-by-step explanation:

oranges sell 8 for 1.84$

so,

1 unit orange =\tt{\dfrac{1.84}{8}=0.23\$ } ⠀

3 0
2 years ago
Will give brainliest <br> A ?<br> B?<br> C ?
dolphi86 [110]

Answer:

A: 180°         B: 360°         C: 540°

Step-by-step explanation:

A: The measures of interior angles of a triangle sum to 180°. Since figure ABC is a triangle, the interior angles of figure ABC sum to 180°.

B: We can see the quadrilateral ACDE is a trapezoid. If you can see, the trapezoid can be split into two triangles if you connect points C and E. As U mentioned before, the measures of interior angles of a triangle sum to 180°. Since we know figure ACDE can be split into <u>two triangles</u> we have to do: 180x2 which is 360°.

C: Now that we know the Pentagon ABCDE can be split into 3 triangles(1 from figure ABC and 2 from figure ACDE), we have to multiply 180 by 3 because like I mentioned before, the measures of interior angles of a triangle sum to 180°. So, 180x3=540°.

5 0
2 years ago
Read 2 more answers
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
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