Recall your d = rt, distance = rate * time
one car is going at 55kph, at say hmmm "t" time
the second car zooms by at 75kph, an hour later, thus " t + 1 "
notice, overtaking the 1st car, simply means, the second car comes from behind approaches the first car from behind and "gets there", at that very second, both cars have travelled a distance, say "d"
if the first car travelled "d" kilometers
for the second car to "get there" has to had travelled "d" distance as well

solve for "t"
Answer:
im kind of rusty on this math but i think the equation would be y=-5x+b i forgot how to find b tho :( im sorry
12^2 - 6^2 * 3^4 + 5^3
(144) - (36) * (81) + (125)
144 - (36 * 81) + 125
144 - 2916 + 125
-2,772 + 125
-2,647
I think A since working backwards and looking for a pattern wouldn't help, maybe C but im not sure