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lakkis [162]
2 years ago
5

A= 5,000 (1+.002*10)

Mathematics
1 answer:
Aneli [31]2 years ago
3 0
I think The answer is 5100
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Use the zero product property to find the solutions to the equation 2x2 + x-1 = 2
algol [13]

Answer:

see explanation

Step-by-step explanation:

Given

2x² + x - 1 = 2 ( subtract 2 from both sides )

2x² + x - 3 = 0

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 × - 3 = - 6 and sum = + 1

The factors are - 2 and + 3

Use these factors to split the x- term

2x² - 2x + 3x - 3 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) + 3(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

3 0
2 years ago
Read 2 more answers
Find the measure of each side of this triangles. Answer in exact form. ​ Find x and y
Firdavs [7]

Answer:

x = 24/√3

4√3 = y

Step-by-step explanation:

We are given that this is a right triangle as well as two angles and a side.

Given that the angles in a triangle add up to 180 degrees, and a right angle is 90 degrees, we can say that the missing angle is equal to

(180-90-30)  = 60 degrees

Next, given sohcahtoa, we can say that

sin(30) = opposite/hypotenuse = y/x

cos(30) = adjacent/hypotenuse = 12/x

tan(30) = opposite/adjacent = y/12

We want to only have one variable per equation so we can solve for the variable, so we can use

cos(30) = 12/x and tan(30) = y/12

Starting with cos(30) = 12/x, we can multiply both sides by x to remove the denominator to get

cos(30) * x = 12, and divide both sides by cos(30) to isolate the x and get

x = 12/cos(30). Next, cos(30) = √3/2, so we have

x = 12/(√3/2)

x = (12/1) / (√3/2)

x = (12/1) * (2/√3)

x = 24/√3

For y, we have

tan(30) = y/12

multiply both sides by 12 to isolate the y and remove the denominator

tan(30) * 12  = y

√3/3 * 12 = y

√3 * 4 = y

4√3 = y

4 0
3 years ago
Explain how you can compare the size of a product to the size of a factor when multiplying fractions without actually doing the
Advocard [28]
<span>Explain how you can compare the size of a product to the size of a factor when multiplying fractions without actually doing the multiplication. Include a model.
tbh idek

</span>
3 0
2 years ago
In january of one winter, 3/10 of a wood pile was used in a wood stove. In February, 2/5 of the wood pile was used. What part of
arsen [322]
2/5 is equivalent to 4/10 so at the end of February 4/10 was used up
And at the end of January, 3/10 was used
so 4/10 + 3/10 = 7/10

At the end of February, 7/10 of the wood was used
6 0
3 years ago
Write in slope-intercept form the equation of the line that passes through the given points. (2,1) and (0,7)
Romashka [77]

Answer:

y= -3x +7

Step-by-step explanation: calculate for the difference in slope and you already had your y intercept

3 0
2 years ago
Read 2 more answers
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